Voltage divider; missing capacitor

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mathman44
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Homework Statement



Circuit schematic of a voltage divider with input pulse Vi at left and output Vo at right, a 9M resistor from node A to node B, a 1M resistor to ground, and a 100 pF capacitor across the output, with a sketch of a skewed pulse waveform labelled Vi against t.


I can't seem to get a start on this. Could anyone provide a hint or something to get me started? Thanks...
 
I don't entirely get this questions either...does the fact that the output is an exact reduced copy mean that if we restrict ourselves to sinusoidal input, for any input frequency, there is no phase difference between the input and output waveforms?
 
Anybody? I tried setting the "right" impedance equal to 1/9th of the "left" impedance to reform the voltage divider but this is a huge mess.
 
mathman44 said:
Anybody? I tried setting the "right" impedance equal to 1/9th of the "left" impedance to reform the voltage divider but this is a huge mess.

You can do it that way. It's easier to work with conductivity: 1/impedance

The "right" conductivity is [itex]10^{-6} + j \omega 10^{-10}[/itex]

The conductivity between A and B should be 9 times that.
 
You want the imaginary parts of the complex impedences to be in the same ratio as the real parts; 9 to 1.