Volume Hypersphere: 4D Sphere Equation

[Einstein's Cat]

What is the equation used to calculate the volume of a four- dimensional "sphere," or hypersphere?

 

[micromass]

What do you mean with volume?

Anyway, https://en.wikipedia.org/wiki/N-sphere#/media/File:N_SpheresVolumeAndSurfaceArea.png

 

[Einstein's Cat]

What do you mean with volume?

Anyway, https://en.wikipedia.org/wiki/N-sphere#/media/File:N_SpheresVolumeAndSurfaceArea.png

Thank you! And I believe volume to be the extent of space the hypersphere would occupy with units cm^4. Please correct me if I'm wrong.

 

[micromass]

Thank you! And I believe volume to be the extent of space the hypersphere would occupy with units cm^4. Please correct me if I'm wrong.

You're not wrong, but the situation is ambiguous. Consider the usual sphere. The volume has unit $cm^3$ and its area has units $cm^2$. When we get to the hypersphere, the number analogous to the surface area is the volume and is measured in $cm^3$. What you want is the number analogous to the volume and which is measured in $cm^4$. I understand completely the desire to call this volume. Mathematicians call it the 4-dimensional Lebesgue measure.

 

[mathwonk]

here are some notes i wrote on this topic:
just as a 3 ball is swept out by revolving half a disc around a line, so a 4 ball is generated by revolving half a 3 ball.
moreover the volume of the solid of revolution can be computed by knowing where the center of mass is. then we can
use Archimedes’ trick to do a calculation that Archimedes could have done. Namely he showed
that the volume of half a 3-ball equals the difference of the volumes of a cylinder minus that of a
cone. Now the center of mass of a cylinder is obviously half way up, and Archimedes knew that
just as the center of mass of a triangle is 1/3 of the way up from the base, the center of mass of a
cone is ¼ the way up from the base.
Thus we can use centers of mass and subtraction to get the volume of a 4-ball. I.e. a cylinder of
height R and base radius R has center of mass at height R/2, and volume πR^2.R, so revolving it
around an axis at its base gives 4 dimensional volume of 2π(R/2).πR^2.R = π^2.R^4. Now the
inverted cone of height R and base radius R has center of mass at distance ¼ of the way from its
base, hence distance (3R/4) from the axis, and volume (1/3)πR^2.R. Thus revolving it generates
a 4 dimensional volume equal to (2π)(3R/4).(1/3)πR^2.R = (1/2)π^2.R^4. Subtracting the
volume of the revolved cone from that of the revolved cylinder, gives the 4 dimensional volume
of the revolved half 3-ball, i.e. the volume of the full 4-ball as π^2.R^4 - (1/2)π^2.R^4 =
(1/2)π^2.R^4.