Volume of solid formed by revolution of one loop of Lemniscate of bernoulli

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SUMMARY

The volume of the solid formed by the revolution of one loop of the Lemniscate of Bernoulli, defined by the equation r² = a²cos(2θ), can be calculated using the formula for volumes of solids of revolution. The integration limits are from 0 to π/4. A suggested substitution for simplifying the integration process is u = √2 cos(θ), along with the trigonometric identity cos(2θ) = 2cos²(θ) - 1 to facilitate the calculation.

PREREQUISITES
  • Understanding of polar coordinates and curves
  • Familiarity with integration techniques in calculus
  • Knowledge of trigonometric identities
  • Experience with volume of revolution formulas
NEXT STEPS
  • Study the derivation of the volume of solids of revolution formula
  • Practice integration techniques involving trigonometric substitutions
  • Explore the properties of polar curves, specifically the Lemniscate of Bernoulli
  • Learn about advanced integration methods, including substitution and trigonometric identities
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Mathematics students, calculus learners, and anyone interested in geometric applications of integration and polar coordinates.

raghavhv
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Hello ppl. I have a problem in finding out the volume of solid formed by the revolution of one loop of lemniscate of bernoulli ( r²=a²cos2θ) about the initial line θ =0
Using the relevant forumula for the volume of the solid generated by the revolution of one loop of the polar curve about the initial line,

http://img357.imageshack.us/img357/4228/93696380jt5.jpg ,

where V is the volume of the solid and π/4 and 0 are the upper and lower limits respectively.

In this problem ,

http://img88.imageshack.us/img88/6624/19344682ul0.jpg

But i am not able to integrate further. I am kinda stuck here. What substitution should i take?Please help me.
 
Last edited by a moderator:
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raghavhv said:
Hello ppl. I have a problem in finding out the volume of solid formed by the revolution of one loop of lemniscate of bernoulli ( r²=a²cos2θ) about the initial line θ =0



Using the relevant forumula for the volume of the solid generated by the revolution of one loop of the polar curve about the initial line,

http://img357.imageshack.us/img357/4228/93696380jt5.jpg ,

where V is the volume of the solid and π/4 and 0 are the upper and lower limits respectively.




In this problem ,

http://img88.imageshack.us/img88/6624/19344682ul0.jpg

But i am not able to integrate further. I am kinda stuck here. What substitution should i take?Please help me.

Try using the following trig identity:

cos(2 \theta )=2cos^2( \theta )-1

And then use a substitution like u \equiv \sqrt{2} cos( \theta )
 
Last edited by a moderator:

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