Volume Rate Problem: Find Change When r=6 & 24 Inches

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Homework Help Overview

The problem involves determining the rate of change of the volume of a sphere as its radius increases over time. The specific rates of change are to be evaluated at two different radii: 6 inches and 24 inches.

Discussion Character

  • Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the derivation of the volume formula and the application of the chain rule to find the rate of change of volume with respect to time. There are questions about the accuracy of the calculations and potential typographical errors in the results.

Discussion Status

Some participants express confidence in the method used, while others suggest verifying the numerical results. There is acknowledgment of a possible typo in one of the calculations, prompting further clarification.

Contextual Notes

Participants are working under the constraints of a homework assignment, which may influence their approach and the level of detail in their discussions.

KatieLynn
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Homework Statement



The radius r of a sphere is increasing at a rate of 2 inches per minute. Find the rate of chance of the volume when r=6 and r=24 inches.

Homework Equations



V=(4/3)(pi)(r^3)

The Attempt at a Solution



This is what I did, I would appreciate it if someone could tell me if it is correct.

So the volume of a sphere is V=(4/3)(pi)(r^3)

So the first thing I did was derive the equation and got this...

(dv/dt)=(4/3)(3)(pi)(r^2)(dr/dt)

Simplifying it and plugging in 2 for (dr/dt) i got...

(dv/dt)=(8)(pi)(r^2)

So then I just plugged in the r and got 288pi and 4680pi, I have a feeling I've done this terribly wrong though :(
 
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I didn't check your numbers, but your method seems fine to me. However, you might want to get a second opinion before you go and write it in stone.
 
It all looks good to me to. Except for when the radius is 24 I got 4608. Maybe you just had a typo there?
 
yes sorry that was a typo, thanks! :)
 

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