Volumetric expansion Kelvin required?

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SUMMARY

The discussion centers on calculating the volumetric expansion of gasoline in a steel gas tank due to temperature changes from 11.5 °C to 37.6 °C. The formula used is ΔV = β(V0)ΔT, where β for gasoline is 950 x 10^-6. The user initially questioned whether temperatures should be converted to Kelvin, but it was clarified that the change in temperature (ΔT) remains the same in both Celsius and Kelvin. Additionally, the impact of the steel tank's volume change on the overall calculation was highlighted as a crucial factor.

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  • Understanding of volumetric expansion principles
  • Familiarity with the formula ΔV = β(V0)ΔT
  • Knowledge of temperature scales (Celsius and Kelvin)
  • Basic concepts of thermal expansion in solids and liquids
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  • Explore how to account for the expansion of both liquids and their containers.
  • Study practical applications of volumetric expansion in automotive engineering.
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Volumetric expansion Kelvin required?

Homework Statement



Suppose that the steel gas tank in your car is completely filled when the temperature is 11.5 °C. How many gallons will spill out of the 20.9- gallon tank when the temperature rises to 37.6 °C?

Homework Equations



βgasoline = 950 x10-6
ΔV = β(V0)ΔT

The Attempt at a Solution



ok so this rele seemed like a plug and jug question to me and i just can't figure out where i went wrong. This is what I did, my only questions are where did i go wrong or maybe are the temperatures supposed to be in Kelvins or would Celsius work to?

(950*10^-6)*(20.9)*(26.1)
why isn't this right?

Thanks yall
 
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Since the size of a degree K and a degree C are the same, ΔT will be the same regardless of scale used.

Did you figure in the change in volume of the steel tank? Both are going to change (by different amounts) when the temperature changed.
 

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