1. The problem statement, all variables and given/known data The coefficient of volume expansion of olive oil is 0.68 × 10-3 K-1. A 1-liter glass beaker is filled to the brim with olive oil at room temperature. The beaker is placed on a range and the temperature of the oil and beaker increases by 25 C°. As a result, 0.0167 liters of olive oil spill over the top of the beaker. What is the coefficient of linear expansion of glass? 2. Relevant equations ΔV = βViΔT ΔV = (3α)ViΔT β = Coefficient of Volume Expansion α = Coefficient of Linear Expansion 3. The attempt at a solution Vi = 1.0 L (for both olive oil and the beaker) Ti = 20°C = 293.15 K ΔT = 25°C = 298.15 K Vlost = 0.0167 L βolive = 0.68x10-3 K-1 αglass = ? Calculate volume expansion of beaker ΔVolive = (0.68x10-3 K-1) * (1.0 L) * (298.15 K) = 0.202742 L ΔVglass = ΔVolive - Vlost = 0.202742 L - 0.0167 L = 0.186042 L (Volume increase for glass beaker) Calculate Coefficient of Linear Expansion for Glass Beaker 0.186042 L = (3αglass)(1.0 L)(298.15 K) 0.186042 L = 894.45 L⋅K * αglass αglass = 0.186042 L / (894.45 L⋅K) = 0.000208 / K = 2.1x10-4 K-1 This is very close to one of the actually answers (there are 5). One of them is 2x10-5 K-1. The teacher has said that he has removed the correct answer for some of the questions, and that we are to explain why are answer is correct if that is the case. Is my answer correct? If not, what did I do wrong?