Vrms = 0.5 Vmax for Half Wave Rectifier: Proof

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SUMMARY

The discussion focuses on proving that the root mean square (Vrms) voltage for a half-wave rectifier equals 0.5 times the maximum voltage (Vmax). Participants clarify that the half-wave rectifier can be represented as a piecewise function of time, where V(t) equals Vmax*sin(ωt) for the first half of the cycle and 0 for the second half. The calculation of Vrms involves integrating the square of this function over one complete cycle, leading to the conclusion that Vrms = 0.5 Vmax.

PREREQUISITES
  • Understanding of sinusoidal waveforms
  • Knowledge of piecewise functions
  • Familiarity with root mean square (RMS) calculations
  • Basic principles of rectification in electrical engineering
NEXT STEPS
  • Study the derivation of RMS values for different waveforms
  • Learn about full-wave rectification and its voltage characteristics
  • Explore the impact of load resistance on rectifier performance
  • Investigate the use of simulation tools like LTspice for rectifier analysis
USEFUL FOR

Electrical engineering students, circuit designers, and anyone interested in understanding rectifier circuits and their voltage characteristics.

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Homework Statement


How to prove that Vrms = 0.5 Vmax for half wave rectifier


Homework Equations





The Attempt at a Solution


I know the graph of half wave rectifier is just the upper part or lower part of sinusoidal wave. But I don't have clue to prove it..

Thanks
 
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So that means that for a half-wave rectifier you can define voltage as a piecewise function of time:
[tex] V(t) = \left\{ \begin{array}{cc}V_{max}sin({\omega}t),&\mbox{ if } 0 \leq t \leq \frac{T}{2}\\0,&\mbox{ if } \frac{T}{2} < t \leq T\end{array}\right.[/tex]

And it's a fairly straightforward calculation to find the RMS value of the function:
[tex] \sqrt{\frac{1}{T}\int_{0}^{T}[V(t)]^2dt[/tex]
 
I get it now

Thanks a lot, JaWiB ! :smile:
 

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