What is the geometry of AsH3 according to the VSEPR model?
The Attempt at a Solution
As has 5 valence electrons and H has one. The molecule therefore has four sets of electron pairs, whereof one is unshared. This gives a tetrahedral structure where the As-H angles are 107 degrees.
However, according to the solutions manual the geometry is triangular planar. Why?
I also have a problem with the geometry of OF2. Here, there are four sets of electron pairs, whereof two are unshared. I would expect the geometry of this molecule to be bent, but it's linear according to my book.