What Is the Actual Bond Angle in SeCl2 According to VSEPR Theory?

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Discussion Overview

The discussion focuses on predicting the actual bond angle in selenium dichloride (SeCl2) using VSEPR theory. Participants explore the relationship between lone pairs and bond angles, as well as the implications of different molecular geometries.

Discussion Character

  • Homework-related
  • Exploratory
  • Technical explanation

Main Points Raised

  • One participant attempts to draw the Lewis structure of SeCl2 and suggests that the bond angle is likely between 90° and 109° due to the presence of lone pairs.
  • Another participant expresses uncertainty but feels intuitively that the initial assessment may be correct.
  • A later reply confirms that lone pairs reduce the ideal tetrahedral bond angle of 109.5° by approximately two to four degrees, supporting the assumption that option D (less than 109°) is correct.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the exact bond angle, though there is agreement that lone pairs influence the bond angle and that it is likely to be less than 109°.

Contextual Notes

The discussion does not resolve the exact bond angle due to varying interpretations of the influence of lone pairs and the specifics of VSEPR theory applications.

Who May Find This Useful

Students studying molecular geometry, VSEPR theory, or those interested in the bonding characteristics of selenium compounds may find this discussion relevant.

MysticDude
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Homework Statement


Predict the actual bond angle in SeCl2 using the VSEPR theory.
a. more than 120°
b. between 109° and 120°
c. between 90° and 109°
d. less than 109°


Homework Equations





The Attempt at a Solution


So I tried to draw the Lewis Structure of the chemical and then the model of it. I also know that lone pairs made the bond angle smaller by about 2°.

I hope that this is the right structure:
[PLAIN]http://img101.imageshack.us/img101/7538/pretest4num4.png

Since the bond angle of a tetrahedral molecule is 109.5°, I would think that it lowered bond angles would be around 90° to 109°.

Any help is appreciated.
 
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Any help? Please and thanks.
 
I hate to answer when I am only partially sure. Intuition tells me you are OK.
 
Thanks for the help Borek :D
 
yes you are correct. the lone pairs reduce the tetrahedral ideal angle of 109.5o between atoms by about two or four degrees, depending on the individual atoms bonded together. So generally you are correct to assume that D is right.
 

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