Wald's Mistake on Einstein Tensor pg 97?

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Discussion Overview

The discussion revolves around a potential mistake made by Wald in his computation of the Einstein tensor components, specifically ##G_{ii}##, in the context of a metric defined by ##g = -d\tau^2 + a^2(\tau)(dx^2 + dy^2 + dz^2)##. Participants explore the implications of Wald's assumptions and calculations.

Discussion Character

  • Debate/contested

Main Points Raised

  • One participant questions Wald's assertion that ##G_{ii} = R_{ii} - \frac{1}{2}R##, suggesting that this implies ##g_{ii} = 1##, which contradicts the metric where ##g_{ii} = a^2(\tau)##.
  • Another participant clarifies that Wald is calculating the projection of the Einstein tensor on a homogeneous hypersurface using a unit vector tangent to this hypersurface, which leads to a different interpretation of the components.
  • A later reply acknowledges a personal oversight in understanding the context of Wald's calculations.
  • One participant expresses a general skepticism towards attributing mistakes to Wald, favoring self-reflection over criticism of the author.

Areas of Agreement / Disagreement

Participants do not reach a consensus on whether Wald made a mistake; instead, they present differing interpretations of his calculations and assumptions.

Contextual Notes

There are unresolved aspects regarding the definitions and conditions under which Wald's calculations are made, particularly concerning the projection of the Einstein tensor and the implications of the metric components.

JonnyG
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On page 97, Wald is computing the component ##G_{ii}## where ##1 \leq i \leq 3## of the Einstein tensor, assuming that the metric is given by ##g = -d\tau^2 + a^2(\tau)\big(dx^2 + dy^2 + dz^2)## where ##a## is the time evolution function. He writes:

##G_{ii} = R_{ii} - \frac{1}{2}R##. But if ##G_{ii} = R_{ii} - \frac{1}{2}R## then that must mean that ##g_{ii} = 1##, which isn't necessarily true, as ##g_{ii} = a^2(\tau)##. Did he make a mistake?
 
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In my copy he is calculating the projection of the Einstein tensor on a homogeneous hypersurface, using a unit (!) vector tangent ##s## to this hypersurface. That is something else than just calculating the spatial components! So instead of ##g_{ii}=1##, he obtains (in his notation) ##g_{**}=1##, which is the condition of unity ##g_{**} \equiv g_{ab}s^a s^b=1## defining this projection.
 
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Thanks. I was being sloppy.
 
When you can choose between "I am sloppy" or "Wald was sloppy", my experience is that the first explanation is more trustworthy.
 
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