Wankel/rotary engine efficiency

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Discussion Overview

The discussion revolves around the efficiency of rotary engines, specifically the Wankel engine, in comparison to traditional gasoline and diesel engines. Participants explore various aspects of engine efficiency, including calculations, thermodynamic principles, and performance metrics such as power output and torque.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • Some participants suggest that the efficiency of a rotary engine can be determined similarly to other heat engines by measuring energy output and fuel heat content.
  • There is a claim that rotary engines, like the RX8, demonstrate impressive power-to-weight ratios, but concerns about emissions and fuel efficiency are also noted.
  • Some participants argue that diesel engines are more efficient than gasoline engines due to higher compression ratios, which can be supported by thermodynamic efficiency formulas.
  • A question is raised about whether the compression ratio or the temperature of combustion products is more responsible for higher efficiency, with a note that both are interrelated.
  • One participant cautions against directly comparing the displacement of Wankel engines to traditional engines due to differences in how displacement is measured.
  • Another participant challenges the notion of rotary engines being efficient, providing comparisons to conventional engines that suggest lower fuel economy for rotary engines.

Areas of Agreement / Disagreement

Participants express differing views on the efficiency of rotary engines compared to traditional engines, with some asserting that rotary engines are more efficient while others argue they are less efficient. The discussion remains unresolved with multiple competing perspectives on the topic.

Contextual Notes

Participants mention the complexity of calculating the compression ratio for Wankel engines due to their geometry, and there are references to the need for sophisticated measurements to obtain gas temperatures and pressures in the Otto cycle.

Who May Find This Useful

Individuals interested in automotive engineering, thermodynamics, and engine performance analysis may find this discussion relevant.

williamcarter
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I was just wondering how we can find out the efficiency of a rotary engine?

Obvious, it is more efficient than a gasoline/diesel engine.For example the RX8 on 1.3 L in 2 rotors get 250 hp which is quite impressive for that capacity,also it works in 4 stroke,and the power to weight ratio is good.The only disadvantage would be the pollution that occurs, due to emmisions.

From my knowledge the diesel is more efficient than a gasoline due it's bigger compression ratio , hence more torque at lower revs.This can be proven thermodinamically using the efficiency formulas that imply compression ratio.

I am curious what types of calculations would be required to find out the efficiency of such engine , because I would like to plot a Power output(HP) vs Tq(torque) diagram,on different revs.
 
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williamcarter said:
I was just wondering how we can find out the efficiency of a rotary engine?

The same as any other heat engine. Measure the amount of energy (or work) produced in a given amount of time and the theoretical amount of heat which can be furnished from the quantity of fuel used. The resulting efficiency can then be determined by a simple calculation.
Obvious, it is more efficient than a gasoline/diesel engine.For example the RX8 on 1.3 L in 2 rotors get 250 hp which is quite impressive for that capacity,also it works in 4 stroke,and the power to weight ratio is good.The only disadvantage would be the pollution that occurs, due to emmisions.
Maybe. Some impressive strides have been made recently with electronic engine controls which allow conventional engines to boost power output while not adversely affecting fuel economy. This suggests that an overall improvement of thermodynamic efficiency for these engines has occurred.

The tiny Ford EcoBoost 3-cylinder 1 liter engine is turbocharged and can produce as much as 138 HP in certain versions, yet the engine itself weighs less than 100 kg or so.

https://en.wikipedia.org/wiki/Ford_EcoBoost_engine
From my knowledge the diesel is more efficient than a gasoline due it's bigger compression ratio , hence more torque at lower revs.This can be proven thermodinamically using the efficiency formulas that imply compression ratio.

I am curious what types of calculations would be required to find out the efficiency of such engine , because I would like to plot a Power output(HP) vs Tq(torque) diagram,on different revs.

The same type of calculations can be done to analyze a Wankel engine as to analyze a piston engine. Both types of engine use the Otto cycle, but it is a tad more difficult to calculate the compression ratio of a Wankel engine, given the complex geometry of the rotor.

I'm not sure what plotting torque and power will do for you.

In metric units:

##Power = \frac{2\pi ⋅ Torque ⋅ RPM}{60}##

Power is in watts and torque is measured in Newton-meters. RPM of course is engine speed in revolutions per minute.
 
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Is it really the compression ratio that is responsible for higher efficiency, or is it higher temperature of the combustion products? (Not that these are completely unrelated, but one is a cause and the other is the effect).
 
Borek said:
Is it really the compression ratio that is responsible for higher efficiency, or is it higher temperature of the combustion products? (Not that these are completely unrelated, but one is a cause and the other is the effect).
Well, a lot of the thermo theory for the Otto cycle uses the compression ratio to calculate the state points of the cycle. The CR is a geometric property of the actual machine and is easy to calculate/determine. You could use gas temperatures and pressures at key points in the cycle to describe it, but this data is much more difficult to come by without taking some sophisticated measurements.
 
williamcarter said:
For example the RX8 on 1.3 L in 2 rotors get 250 hp which is quite impressive for that capacity
Be careful when you compare the displacement of a Wankel engine to a typical 4-stroke engine. The first one represents the displacement per revolution and the second one is the displacement per cycle (which is 2 revolutions). In this case, there is a factor of 2 between the two. More info on this page (click (more) next to Displacement and Comparing Wankel and piston engines).
 
williamcarter said:
Obvious, it is more efficient than a gasoline/diesel engine.For example the RX8 on 1.3 L in 2 rotors get 250 hp which is quite impressive for that capacity,also it works in 4 stroke,and the power to weight ratio is good.The only disadvantage would be the pollution that occurs, due to emmisions.

The rotary is actually very inefficient (as anyone who's owned one will tell you, they are thirsty!).

some comparisons to regular 4 stroke petrol cars:
A golf GTI has similar power & weight as the RX8 but has 55% better fuel economy.
A Corvette has similar economy as the RX8 but almost twice as much power.

The long story:

While comparing peak power to economy isn't a perfect proxy for efficiency I think it'd still be representative.
 

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