Was the Angle Discovered? Thread Closed Due to Existing Problem

[AzureSekki]

Homework Statement

How did they get all the angle here in this problem
Except for the angle 65° which is given it's not stated on how they got it so im having a hard time to understand the problem

Relevant Equations

Find angle

 

[BvU]

Homework Statement:: How did they get all the angle here in this problem

That's a statement of your problem, not of the homework problem.
Provide a complete problem statement

given:​

knowns:​

unknowns:​

I am having a hard time to understand the problem

This way, so am I !

$C$ doesn't exist ?

 

[Lnewqban]

Didn't you solve this same problem this morning?
Finding all those angles may not be the best way to learn about sum of vectors and to solve the problem.

https://www.physicsforums.com/threads/vector-resolution-onto-axes-not-at-right-angles.984637/

 

[Master1022]

Hi,

So I am slightly confused by some of the lettering, but perhaps I am missing something. If you are told that $\angle BON = 65$, then do you understand the working to find $\angle AOC = 30 degrees$ (I am assuming point C is where point N is)?

If we can accept that, then I think the easiest way to get $\angle BOA$ is just to consider $\angle BON = \angle BOA + \angle AON$. Solving this yields the same answer of 35 degrees.

I believe they have labeled the 115 degrees by using the fact that line segments BA and ON are parallel and $\angle OBA$ and $\angle BON$ are therefore supplementary ('internal' angles of parallel lines add up to 180 degrees), so they could get 115 from $\angle OBA = 180 - 115$

Hope that answers your question. If not, let me know and I will respond appropriately.

Kind regards

 

[BvU]

If not, let me know and I will respond appropriately.

Post the complete problem statement !

 

[AzureSekki]

Hi,

So I am slightly confused by some of the lettering, but perhaps I am missing something. If you are told that $\angle BON = 65$, then do you understand the working to find $\angle AOC = 30 degrees$ (I am assuming point C is where point N is)?

If we can accept that, then I think the easiest way to get $\angle BOA$ is just to consider $\angle BON = \angle BOA + \angle AON$. Solving this yields the same answer of 35 degrees.

I believe they have labeled the 115 degrees by using the fact that line segments BA and ON are parallel and $\angle OBA$ and $\angle BON$ are therefore supplementary ('internal' angles of parallel lines add up to 180 degrees), so they could get 115 from $\angle OBA = 180 - 115$

Hope that answers your question. If not, let me know and I will respond appropriately.

Kind regards

Thanks for the clarification

 

[Mark44]

Thread closed, as this is a new thread about an existing problem.