Watt needed to heat up an iron, correct?

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SUMMARY

The calculation for heating an iron cube measuring 1.3cm x 1.3cm x 0.7cm involves determining its volume, mass, and the energy required to raise its temperature. The volume is calculated as 1.183cm³, and with a density of 7.8g/cm³, the mass is found to be 9.2274 grams. Using the formula Q=mcT, where c for iron is 0.450 J/(g·K) and the temperature difference is 160°C, the total energy required is 662.4 Joules. To heat the iron in 60 seconds, a power of 11.04 Watts is necessary, confirming the calculation is accurate.

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an IRON cube with (Length 1.3cm Width 1.3cm Height 0.7cm) so
Volume = 1.183cm^3

density of an IRON = 7.8gm/cm^3 so
Mass = 9.2274gram

Q=mcT c for iron = 0.450 J/(g·K), T difference = 160 degree celsius
Q=9.2 . 0.45 . 160
Q=662.4Joule

1Joule = 1 Watt.second

so if i need to heat up an IRON from 20C to 180C (T difference = 160 degree celsius) in 60second

so i need (662.4/60) = 11.04Watt

correct? please advice..

thanks
 
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Yes that should be correct.