- #1

- 1

- 0

Volume = 1.183cm^3

density of an IRON = 7.8gm/cm^3 so

Mass = 9.2274gram

Q=mcT c for iron = 0.450 J/(g·K), T difference = 160 degree celsius

Q=9.2 . 0.45 . 160

Q=662.4Joule

1Joule = 1 Watt.second

so if i need to heat up an IRON from 20C to 180C (T difference = 160 degree celsius) in 60second

so i need (662.4/60) = 11.04Watt

correct? please advice..

thanks