Wave equation for an elastic rod

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thomas19981
Handwritten derivation titled MY SOLUTION: a sketch of a rod element of length δx stretched to δx+δξ, followed by equations relating stress, strain, F = ma and mass density, ending with a partial differential equation in ξ and x.
1. Homework Statement

The figure below shows a section of a thin, elastic rod of density ##\rho##, cross sectional area ##A##, and modulus of elasticity ##E##.
Two stacked diagrams of a rod segment from O to R: the upper shows points P and Q with spacing marked delta x at position x; the lower shows the displaced points P' and Q' at x+zeta, with spacing delta x + delta zeta.

By considering the net force acting on an element of the rod, derive the wave equation governing its longitudinal motion:

##\frac{\partial^2(\xi)}{\partial t^2}=\frac{E}{\rho}\frac{\partial^2(\xi)}{\partial x^2}##

where ##\xi## is the displacement of the medium from its equilibrium position.

Homework Equations

The Attempt at a Solution


My solution is inserted as an image but I can't see where I'm going wrong with this question.
Many thanks in advance.



 
Attachments
  • Two stacked diagrams of a rod segment from O to R: the upper shows points P and Q with spacing marked delta x at position x; the lower shows the displaced points P' and Q' at x+zeta, with spacing delta x + delta zeta.
    upload_2017-11-9_15-42-49.png
    4.7 KB · Views: 1,116
  • Handwritten derivation titled MY SOLUTION: a sketch of a rod element of length δx stretched to δx+δξ, followed by equations relating stress, strain, F = ma and mass density, ending with a partial differential equation in ξ and x.
    IMG_0098.JPG
    18 KB · Views: 929
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You are missing the fact that there are two forces acting on each element of the rod. One to the left and one to the right. Both are proportional to the strain at their respective locations.
 
Orodruin said:
You are missing the fact that there are two forces acting on each element of the rod. One to the left and one to the right. Both are proportional to the strain at their respective locations.
Orodruin said:
You are missing the fact that there are two forces acting on each element of the rod. One to the left and one to the right. Both are proportional to the strain at their respective locations.
Hi. I've considedered the two forces in the different locations but I seem to be running into a similar problem.
 
Attachments
  • Handwritten derivation on lined paper, rotated sideways, with a sketch of a rod segment of length x·ρ and a second segment of length 2/... marked A and B, and a partial differential equation derivation below.
    image.jpg
    25.4 KB · Views: 520
Can you please write down your work in text rather than attaching it as images? (As stated in the homework rules.) It is very annoying to have to look at a computer screen turned 90 degrees and to read your hand-written things in relatively bad resolution.