Calculating Displacement & Intensity of 1665 Hz Wave

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The discussion focuses on calculating the displacement amplitude and intensity of a sound wave with a frequency of 1665 Hz and a pressure amplitude of 1.13 x 10^-3 Pa. The formula used for displacement amplitude involves pressure amplitude, density, velocity, and angular frequency. The calculated displacement amplitude is 5.25 x 10^-7 m, while the intensity of the wave emitted by the ear is determined to be 1.34 x 10^-10 W/m2. The calculations rely on accurate values for density and angular frequency derived from the frequency. These findings provide insight into the characteristics of sound waves in a specific context.
JasonV
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A sound wave has a frequency of 1665 Hz and a pressure amplitude of 1.13 x 10^-3 Pa. What were (a) the displacement amplitude and (b) the intensity of the wave emitted by the ear?

the equation i used for a is sm=delta(pm)/(vpw)

where p is the density, sm is the displacement amplitude, pm is the pressure amplitude, v is the velocity, and w is the angular frequency.

I could find all of the variables from the equation but the velocity (pm=1.13 x 10^-3, p=1.21, w=2pif=2pi x 1665)
Thanks in advance.
 
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a) The displacement amplitude is 5.25 x 10^-7 m.b) The intensity of the wave emitted by the ear is 1.34 x 10^-10 W/m2.
 
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