Wave Speed Dependency on Distance from Top of Hanging Rope

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The discussion centers on determining the wave speed dependency on the distance from the top of a hanging rope. The initial equation for wave speed, V=(FL/M)^(1/2), is analyzed, leading to the conclusion that V=sqrt(zg) is incorrect. The correct expression for wave speed is SQRT((l-z)g), as the tension in the rope varies with the distance z. Participants emphasize the importance of understanding the tension at different points along the rope, particularly noting that the tension at the top is zero while it is mg at the bottom. The conversation concludes with a suggestion to visualize the problem through free-body diagrams for clarity.
BryMan92
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Homework Statement


The question asks:
There is a rope, of length l, and of mass m hanging from the ceiling. What is the wavespeed dependency on z, the distance from the top?



Homework Equations


I used:

V=(FL/M)^(1/2)



The Attempt at a Solution



V=(m(Z/L)gl/m)^1/2=sqrt(zg)
The answer is:
SQRT((l-z)g)

I do not know how to attain this answer, and any help would be great! Thanks!
 
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Uppercase and lowercase letters generally represent different variables. Stick with using one or the other. Don't switch between them randomly.

According to your work, the tension F in the rope is equal to m(z/l)g. That means at the top where z=0, the tension is F(z=0)=0, and at the bottom, where z=l, the tension is F(z=l)=mg. Does that sound right?
 
vela said:
Uppercase and lowercase letters generally represent different variables. Stick with using one or the other. Don't switch between them randomly.

According to your work, the tension F in the rope is equal to m(z/l)g. That means at the top where z=0, the tension is F(z=0)=0, and at the bottom, where z=l, the tension is F(z=l)=mg. Does that sound right?

My thought process was, that if I have, say L = 10, and Z= 3, that would mean, I would have only have 3/10(mg)...but now that I think about it, that actually means I have 7/10(mg) because the tension is holding 7/10 of the rope. Can I think of it as if I hold my finger at a point z, what is below it is the mass of the string? Thank you!
 
Last edited:
Imagine cutting the rope at a distance z from the top. Draw the free-body diagram for the bottom part of the rope and then solve for F.
 
vela said:
Imagine cutting the rope at a distance z from the top. Draw the free-body diagram for the bottom part of the rope and then solve for F.

Gotcha, thank you very much for your help! :D
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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