# What is the wavelength of a pulse on a hanging rope with changing tension?

• harambe
In summary, a uniform rope of length 12cm and mass 6kg hangs vertically from a rigid support. A block of mass 2kg is attached to the free end of the rope. A transverse pulse of wavelength 0.06m is produced at the lower end of the rope. The wavelength changes and the tension also changes throughout the rope. Using the wave equation, v1/v2=(T1/T2)^1/2, it can be determined that the frequency remains constant all over the rope. This is because if 100 complete waves are sent up, they will all take the same time to reach the top, indicating that the frequency at the bottom is the same as the frequency at the top. The waves
harambe

## Homework Statement

A uniform rope of length 12cm and mass 6kg hangs vertically from a rigid support.A block of mass 2kg is attached to the free end of the rope.A transverse pulse of wavelength 0.06m is produced at the lower end of the rope.What is the wavelength of the rope ,when it reaches the top of the rope

## The Attempt at a Solution

So It is given that the wavelength changes and the tension also changes through out the rope

T(upper segment)= 8g,T(Lower segment)-=2g

The wave equation

v1/v2=(T1/T2)^1/2 {the mass perunit length cancels for this case}

Now velocity of a wave= wavelength X frequency

The wavelength is changing through out the rope and I don't know about frequency so How should I proceed after this...Does the derivation consider the fact that the wave changes velocity at every point on the rope

harambe said:
If 100 complete waves are sent up will they all take the same time to reach the top? What does that tell you about how the frequency at the bottom compares to the frequency at the top?

harambe
They will take same time so frequency should remain constant

harambe said:
They will take same time so frequency should remain constant
Right, so can you now determine the wavelength change?

palkia
The frequency remains same so use the relationship between wavelength and velocity to solve this

yeah and I got my answer now

haruspex said:
If 100 complete waves are sent up will they all take the same time to reach the top? What does that tell you about how the frequency at the bottom compares to the frequency at the top?
The elements in the upper part might vibrate less that the elements at the lower part leading to decrease in the frequency.
I still can't understand how your example leads to the explanation that frequency is constant all over the rope.

pranjal verma said:
The elements in the upper part might vibrate less that the elements at the lower part leading to decrease in the frequency.
I still can't understand how your example leads to the explanation that frequency is constant all over the rope.
The waves might change amplitude, but they will not disappear completely, nor will extra waves appear out of nowhere. If the frequency at the bottom is persistently greater, say, than the frequency at the top then then the number of waves in between must be increasing, without limit.

pranjal verma
haruspex said:
If 100 complete waves are sent up will they all take the same time to reach the top? What does that tell you about how the frequency at the bottom compares to the frequency at the top?
I still can't understand how your example leads to the explanation that frequency is constant all over the rope.
The elements in the upper part might vibrate less that the elements at the lower part leading to decrease in the frequency.
haruspex said:
The waves might change amplitude, but they will not disappear completely, nor will extra waves appear out of nowhere. If the frequency at the bottom is persistently greater, say, than the frequency at the top then then the number of waves in between must be increasing, without limit.
Thank you very much sir.

pranjal verma said:
The elements in the upper part might vibrate less that the elements at the lower part leading to decrease in the frequency.

That is quite vague, so I am not sure what your reasoning is.
What do you mean by vibrating less? Less amplitude, yes, but less often, no.
Start with one pulse sent from the bottom. It takes some time t to reach the top.
Now send the next pulse. Doesn't that also take time t to reach the top?

I agree that all the pulses will take same time to reach the top but how it relates to constant frequency?

pranjal verma said:
I agree that all the pulses will take same time to reach the top but how it relates to constant frequency?
Now consider pulses emitted at times ##t_0, t_0+T, t_0+2T, ...##. They arrive at the top at times ##t_0+t, t_0+t+T, t_0+t+2T, ...##.

So vibration is in vertical direction (up-down) , I thought it was in horizontal axis (left-right).

pranjal verma said:
So vibration is in vertical direction (up-down) , I thought it was in horizontal axis (left-right).
Makes no difference to the argument.

haruspex said:
Makes no difference to the argument.
I see that time period of all the pulses will be same so all the pulses will have same frequency(up-down vibrations) so it is about vertical vibrations and not horizontal with which I confused .

pranjal verma said:
I see that time period of all the pulses will be same so all the pulses will have same frequency(up-down vibrations) so it is about vertical vibrations and not horizontal with which I confused .
It does not matter whether they are vertical or horizontal. The pulses must arrive at the same rate at which they start, so the frequency is the same.

## What is the "wavelength of the pulse"?

The wavelength of the pulse refers to the distance between two consecutive peaks or troughs of a pulse of energy or disturbance.

## How is the wavelength of a pulse calculated?

The wavelength of a pulse can be calculated by dividing the speed of the pulse by its frequency. This can be represented as λ = v/f, where λ is the wavelength, v is the speed, and f is the frequency.

## What factors can affect the wavelength of a pulse?

The wavelength of a pulse can be affected by the medium through which it travels, the amplitude of the pulse, and the frequency of the pulse.

## Why is the wavelength of a pulse important to know?

The wavelength of a pulse is important because it can help us understand the behavior and characteristics of waves. It also plays a role in determining how the pulse will interact with its surroundings and other pulses.

## How does the wavelength of a pulse differ from the wavelength of a continuous wave?

The wavelength of a pulse is the distance between two peaks or troughs of a single disturbance, while the wavelength of a continuous wave is the distance between two consecutive points on a wave that are in phase with each other. Additionally, the wavelength of a pulse can vary depending on the characteristics of the pulse, while the wavelength of a continuous wave remains constant.

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