- #1

Chansudesu

- 3

- 0

## Homework Statement

"...you were presented with a geologist at the bottom of a mineshaft next to a box suspended from a vertical rope. The geologist sent signals to his colleague at the top by initiating a wave pulse at the bottom of the rope that would travel to the top of the rope. The mass of the box is 20.0 kg and the length of the rope is 80.0 m. If a wave pulse initiated by the geologist takes 1.26 s to travel up the rope to his colleague at the top, find the mass of the rope."

m

_{Box}= 20.0kg

L = 80.0m

T = 1.26

## Homework Equations

v = √(F/μ)

∑F = ma

v = λƒ

## The Attempt at a Solution

I'm still trying to figure out how to approach the problem (set up my equations)...

I know that because the rope hangs vertical, the restoring force (weight UNDER a given point) is changing as the wave travels upwards, thus, the velocity is changing as well. So

dv = √(dF

_{Restoring}/μ)

and then we need to find the restoring force:

∑F = T - m

_{Box}g - m

_{Rope}g = 0 (because it's in equilibrium in the y-direction)

T = m

_{Box}g + m

_{Rope}g

At the beginning, the restoring force is only the weight of the box; and at the end, the restoring force is the weight of the box AND the weight of the rope. So

dF

_{Restoring}= dT = w

_{Box}+ (dm

_{Rope})g

And then I tried turning μ = m/L into:

μ = dm/dL -> dm = μdL

but this doesn't get me anywhere.. I do not know what μ is equal to since we don't know the weight and when I put the equations together I get

dv = √[(w

_{Box}+ μdL)/μ] -> dv = √[L(w

_{Box}+ μdL)/ m]

I'm kinda stuck here and I don't think it's in the right direction because I haven't figured out why I was given the period...

Any help would be appreciated ^^