Wave speed of the collision process in a line of cars

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SUMMARY

The discussion focuses on deriving an equation for wave speed in a line of cars at a stoplight, particularly during collision events. The relevant equations mentioned are V=√(T/(m/L)) for wave speed and V=λf, with an emphasis on elastic collisions. The participants clarify that the time factor is crucial, as wave speed approaches infinity as distance approaches zero and approaches the initial speed (v0) as distance approaches infinity. The conversation highlights the need to consider the effects of car length and collision dynamics on wave propagation.

PREREQUISITES
  • Understanding of wave mechanics, specifically wave speed equations.
  • Knowledge of elastic and inelastic collisions in physics.
  • Familiarity with tension, mass, and length in the context of wave propagation.
  • Basic calculus to analyze limits and time factors in wave speed.
NEXT STEPS
  • Study the principles of elastic collisions and their impact on wave speed.
  • Learn about the mathematical modeling of wave propagation in non-deformable bodies.
  • Investigate the effects of varying mass and length on wave dynamics in collision scenarios.
  • Explore advanced topics in wave mechanics, including shock waves and their characteristics.
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Physics students, automotive engineers, and anyone interested in the dynamics of collisions and wave propagation in mechanical systems.

snickersnee
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Homework Statement



I need to write an equation for the at rest at a stoplight. Each car bumps into the one in front of it until the first car in line gets bumped.

Homework Equations


I found these equations for wave speed:
V=√(T/(m/L)), where T is tension, m is mass, L is length
and of course V=λf

The Attempt at a Solution


l8atx.jpg


But both those equations have a time factor, and I wasn't given any time information. All I know is that wave speed needs to approach infinity as x → 0, and wave speed approaches vo as x→∞
Any hints would be appreciated.
 
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snickersnee said:
I found these equations for wave speed:
V=√(T/(m/L)), where T is tension, m is mass, L is length
You don't have a string here.

I think you are supposed to assume that all collisions are either perfectly inelastic or elastic. The latter is easier to study: what is the speed of the first bumped car after the collision? How long does it take to make the next collision?
 
Yes we're assuming elastic collisions. The first bumped car is traveling at v0 because the car behind it transferred all its energy. The time until the next collision is
upload_2015-9-7_19-16-47.png
. I was thinking the total distance would be (4L+3x) and total time would be 3v0/(L+x) but then (total distance)/(total time) gives (4L^2+7xL+3x^2)/3v0 but that doesn't satisfy the limits required.
 
Why should the time change for longer cars (larger L) if the distance between the cars does not change?

Also, your fraction does not have units of time, it has units of inverse time.
 
mfb said:
Why should the time change for longer cars (larger L) if the distance between the cars does not change?

Also, your fraction does not have units of time, it has units of inverse time.

Thanks for your help. I think the time should change for longer cars because the disturbance takes longer to pass through that car, assuming the velocity of the disturbance is constant. And you're right, I should flip the fraction so it becomes
upload_2015-9-8_19-0-9.png
 
If the shock would travel at a speed of v (the same speed as the final car speed), your cars would get completely compressed to a single "disk" in the process - certainly not realistic.
Assume that the cars are incompressible (they cannot get deformed permanently in elastic collisions anyway) - as soon as the back of a car moves, the front moves as well.
 

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