Calculating Wavelength of Electron Emission

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SUMMARY

The discussion focuses on calculating the wavelength of light emitted when an electron recombines with a hole, losing 2.6 eV of energy. The correct formula used is λ = hc/E, where h is Planck's constant (6.63 x 10-34 J·s) and c is the speed of light (3.00 x 108 m/s). A critical point raised is the necessity to convert energy from electron volts (eV) to joules (J) for accurate calculations, as 1 eV equals 1.60217646 x 10-19 J. The final wavelength calculated was 7.65 x 10-26 m, which indicates a high-energy photon.

PREREQUISITES
  • Understanding of quantum mechanics concepts, specifically electron transitions.
  • Familiarity with the formula for wavelength calculation: λ = hc/E.
  • Knowledge of energy unit conversions, particularly from electron volts to joules.
  • Basic proficiency in using scientific notation for calculations.
NEXT STEPS
  • Research the process of converting electron volts to joules in detail.
  • Study the implications of high-energy photons in quantum mechanics.
  • Learn about Planck's constant and its significance in quantum physics.
  • Explore additional examples of electron transitions and their corresponding wavelengths.
USEFUL FOR

Students studying quantum mechanics, physics educators, and anyone involved in calculations related to photon emissions and energy transitions in electrons.

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I need to make sure my method and the formula I have used is correct. Also, my answer for the wavelength seems slightly dodgy. :rolleyes:

Homework Statement


An electron recombines with a hole losing 2.6eV of electrical potential energy. Calculate the wavelength of the light emitted.

Homework Equations


Not given. Equations have to be used ourself.

The Attempt at a Solution


E = \frac{hc}{\lambda}

\lambda = \frac{hc}{E}

\lambda = \frac{(6.63 \times 10^{-34})(3.00 \times 10^8)}{2.6}

\lambda = 7.65 \times 10^{-26}m
 
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Put units on things and make sure they match up. You'll want to convert 2.6eV to joules.
 
You've found the most high energy photon I've ever heard of! ! ! ! Always check the units, you forgot to convert the energy from eV's to Joules.

and I see now that dick just recommended the same thing. . .
 
Last edited:
How would I change eV's to Joules?
 
1eV=1.60217646*10^(-19) joules. That's what google says when I type in 'electron volt', anyway.
 

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