Wavelength, period of vibration in seconds

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Homework Help Overview

The discussion revolves around the relationship between wavelength, wavenumber, and the period of vibration in a physics context. The original poster is attempting to convert wavenumber values into a period using relevant formulas.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the correct interpretation of wavenumber versus wavelength, questioning the units involved in the calculations. There are attempts to clarify the formulas for period and frequency, as well as the appropriate unit conversions.

Discussion Status

Some participants have provided guidance on the correct relationships between wavelength, velocity, and period. There is an ongoing exploration of unit conversions and the implications of using wavenumber in the context of the problem.

Contextual Notes

There is a noted confusion regarding the units of wavenumber and wavelength, with participants highlighting the need for clarity in unit conversions. The original poster's calculations have led to questions about the appropriateness of the formulas being used.

Rick2015
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< Mentor Note -- thread moved to HH from the technical physics forums, so no HH Template is shown >[/color]

Okay, I am having trouble with the units. I have the values for the wavenumber and I am trying to find the period.
These are the formulas that I am trying.
T = 1/f ; f = c/lambda

example: lambda = 3657 cm^-1 ; c = 2.998 x 10^8 m/s
I am doing 2.998 x 10^8 m/s / (3657 cm^1 x (1 cm/0.01m))
however, the unit for frequency is Hz = 1/s
I am getting m^2 on the denominator.
Am I using the right formulas?
thanks!
 
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Rick2015 said:
< Mentor Note -- thread moved to HH from the technical physics forums, so no HH Template is shown >

Okay, I am having trouble with the units. I have the values for the wavenumber and I am trying to find the period.
These are the formulas that I am trying.
T = 1/f ; f = c/lambda

example: lambda = 3657 cm^-1 ; c = 2.998 x 10^8 m/s
I am doing 2.998 x 10^8 m/s / (3657 cm^1 x (1 cm/0.01m))
however, the unit for frequency is Hz = 1/s
I am getting m^2 on the denominator.
Am I using the right formulas?
thanks!

By wavenumber, do you mean wavelength? If so, wavelength has units of meters, not 1/meters.
 
yes. it is the wavelength. But I am getting m^2
 
Rick2015 said:
yes. it is the wavelength. But I am getting m^2

So you are given the wavelength, and want to find the period? Start off with the conversion equation that makes sense in terms of units...

Period <s> = \frac{Wavelength [m]}{Velocity [\frac{m}{s}]}</s>
 
A wavelength has units of meters, not inverse meters.
Inverse meters suggest it is a wavenumber (usually called "k"). You can convert it to a wavelength, or directly use formulas with the wavenumber.
 
berkeman said:
So you are given the wavelength, and want to find the period? Start off with the conversion equation that makes sense in terms of units...

Period <s> = \frac{Wavelength [m]}{Velocity [\frac{m}{s}]}</s>

Not sure why my Latex isn't rendering correctly. It previews fine. Oh well, the old fashioned way:

Period [in seconds] = Wavelength [in meters] / Velocity [in meters/second]

EDIT -- I see now that using [ s ] without the spaces caused a strikethrough... Duh.
 
I got it! Thank you!
 

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