Waves under Boundary Conditions

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SUMMARY

The discussion focuses on the behavior of waves under boundary conditions in a one-dimensional string system, specifically when one end is fixed to a wall and the other is attached to an oscillator. Waves that are not at harmonic frequencies exhibit characteristics similar to stable standing waves but are not resonant, resulting in evanescent modes that decay over distance. The analysis highlights that due to the one-dimensional nature of the string, continuous solutions to the eigenvalue problem are not possible, leading to the conclusion that frequencies between two discrete modes cannot propagate effectively.

PREREQUISITES
  • Understanding of wave mechanics and boundary conditions
  • Familiarity with eigenvalue problems in physics
  • Knowledge of waveguide theory and modes of propagation
  • Basic principles of oscillation and resonance
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  • Explore the mathematical derivation of wave equations for one-dimensional strings
  • Investigate the concept of evanescent waves and their implications in physics
  • Study the behavior of waves in rectangular waveguides and their modes
  • Learn about forced oscillations and their effects on wave stability
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Physicists, engineering students, and anyone interested in wave mechanics, particularly in the context of boundary conditions and oscillatory systems.

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For a string with one endpoint attached to a wall and the other to an oscillator (so that it is under boundary conditions), what is the character of waves that are not at a harmonic frequency?
 
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I was assuming that the waves would be somewhat similar in form to the stable standing waves (considering the forced nodal points), but not as resonant (out of phase from the nearest resonance frequency).
 
If we had a rectangular waveguide, we could solve for the modes of the waveguide that arise due to the boundary conditions. These modes represent the possible solutions of waves that can travel through the waveguide. But since these modes are discrete, it can be a bit confusing on how waves of frequencies between two modes can propagate. What happens is that we discretize the possible wave numbers in say the x and y directions and allow the wave number in the z direction to be continuous. So as we change the frequency, the direction of the wave as it propagates changes slightly so that it bounces around while satisfying the boundary conditions.

The problem with the wave on a string as I see it is that we only have one dimension of freedom, along the length of the string. Thus, we do not have an extra dimension that we can vary freely to allow continuous solutions to the eigenvalue problem. That is to say, if we have two frequencies of waves that satisfy the boundary conditions (driven at one end and a nodal point at the other), then frequencies between those two modes cannot be a solution. Instead, they are evanescent modes, if you were to excite these modes on your string they would die out as they travelled.

You could show this explicitly by solving for the wave equations and you should arise with one that attenuates over time/distance.
 
I see...so altogether, they are not stable enough to exist for the one dimensional case...though, if the oscillator were continuously running, would it sort of be the same as the condition for forced oscillations all across the wave?
 
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