A 88.0 kg person stands on a scale in an elevator. What is the apparent weight in each of the following situations? (a) when the elevator is accelerating upward with an acceleration of 1.40 m/s2 (b) when the elevator is moving upward at a constant speed (c) when the elevator is accelerating downward with an acceleration of 1.70 m/s2 in my text it talks about apparent weight on an elevator and gives the equation: Force Normal = mg + ma then it doesn't say a darn thing afterwords. no example or anything. my attempted solutions: a) a= 9.8 + 1.4 = 11.2 m/s^2 F = (88kg x 9.8m/s^2)+(88kg x 11.2m/s^2)= 1795.2 N b) the elevator isn't moving so the apparent weight would be the same as the normal weight w = mg = 88 x 9.8 = 862.4N c) a = 9.8 - 1.7 = 8.1m/s^2 F = (88 x 9.8)+(88 x 8.1)= 1575.2n i know a and c can't make sense because they are worked the same way and c is greater b. c should be less than b am i using the formula wrong?