Weinberg's Cosmology: Neglecting (1+z(eq)) in Denominator

  • Level: Graduate 
  • Thread starter Thread starter EhsanZ
  • Start date Start date
  • Tags Tags
    Cosmology
Join the discussion
Registration is free. Start your own thread to ask a follow-up.
Sign up Log in
2 replies · 2K views
EhsanZ
Messages
11
Reaction score
0
In equation below
〖H₁〗^2/〖H₀〗^2 =Ω₀(cri) (R₀⁴)/(R₁⁴(1+z(eq)))

Why is the term “(1+z(eq))” negligible in denominator according to the term “ R₁⁴ ” ?

Weinburg did it in his book named "Cosmology".
 
Astronomy news on Phys.org

Discussion

EhsanZ said:
Weinburg did it in his book named "Cosmology".

I would like to see the context, but I don't feel like looking for this by flipping through Weinberg page-by-page. Could you please give the page number?