1. The problem statement, all variables and given/known data A hunter aims directly at a target (on the same level) 38.0m away. (a) If the arrow leaves the bow at a speed of 23.1m/s, by how much will it miss the target? (b) At what angle should the bow be aimed so the target will be hit? Notes: Initial Y velocity is 0m/s. Vi = Vix 2. Relevant equations Kinematic equations 3. The attempt at a solution I was able to solve the first part (a), fairly straightforward. 38m = 23.1m/s * t t = 1.65s Yf = 1/2(-9.8m/s^2)(1.65s^2) = -13.3m, target missed by 13.3 meters. I am mostly having difficulties with the second part. The answer says it is 22.1 degrees, but I don't know how to get to that answer. I tried setting up a triangle of the final velocities and see what that angle would be. Final velocity X: 23.1 m/s Final velocity Y: (-9.8m/s^2)(1.65s) = 16.17m/s Final velocity overall: 28.2m/s tan^-1(x) = 16.17/23.1 = 35 degrees. How should I get to the correct angle of 22.1 degrees?