1. The problem statement, all variables and given/known data You have been stranded on a deserted island. Fortunately, you managed to bring a flare gun. You can see a ship 300. m off shore. Unfortunately, because of the daylight the ship cannot see your flare unless it is within 100. m of the ship. A.) If you fire the flare gun from the shore line with an initial velocity of 161 km/hr at an angle of 33.3 degrees , will they see your flare? (You must show your work in explaining why/why not.) B.) With this same initial speed, is there an angle you could fire that would allow them to see your flare? If so, what is that angle? 2. Relevant equations R= (vi^2sin2(theta))/g 3. The attempt at a solution plugging in the known information i get R=((44.72m/s)^2(sin(66.6))/9.8m/s^2 =187. would this be correct? or is calculating the range just the x distance? and i know 45 degrees is where the max is so for part b) i would plug in 45 degrees into the formula to get around 200. and therefore they'd see the flare. When i initially did this problem i used the formula v^2=u^2+2as u=44.72 m/s (sin(33.3)=24.6 a=-9.8 m/s^2 plugging in i got 0=(25.6^2)+2(-9.8)s s=30.76 and this got me a distance of 30.76 (which is COMPLETELY different than the other formula. what is the correct way? okay, so relooking at this i see that using range is how FAR it goes (horizontally) and the second way i showed is actually showing the max height it hits. so since i'm just looking for the flare to get at least 200.m off shore i'm assuming range is therefore the correct approach. Would this be correct to think?