What are examples of cellular decomposition?

  • Context: Graduate 
  • Thread starter Thread starter quasar987
  • Start date Start date
  • Tags Tags
    Decomposition
Click For Summary
SUMMARY

The discussion focuses on the non-uniqueness of cellular decompositions in CW-complexes. It establishes that while the process of obtaining the n-skeleton X^n from the (n-1)-skeleton X^(n-1) involves gluing n-cells, this process is not unique. However, it concludes that it is impossible to construct X from X^(n-1) using a different number of n-cells, as the open n-cells in X correspond to the connected components of the difference set X\X^(n-1).

PREREQUISITES
  • Understanding of CW-complexes and their skeletons
  • Familiarity with topological concepts such as gluing and cell attachment
  • Knowledge of connected components in topology
  • Basic principles of algebraic topology
NEXT STEPS
  • Study the properties of CW-complexes in algebraic topology
  • Explore the concept of homotopy and its relation to cellular decompositions
  • Learn about the role of connected components in topological spaces
  • Investigate examples of non-unique cellular decompositions in various topological constructs
USEFUL FOR

Mathematicians, particularly those specializing in topology, educators teaching algebraic topology, and students seeking to understand the intricacies of CW-complexes and their decompositions.

quasar987
Science Advisor
Homework Helper
Gold Member
Messages
4,796
Reaction score
32
Say X is a CW-complex. Then for any n, the n-skeleton X^n of X is obtained from the (n-1)-skeleton X^(n-1) by gluing some n-cells on X^(n-1) along their boundary.

From what I read, it seems that the way to obtain X^n from X^(n-1) in this way is not unique.

Is this non-uniqueness superfluous (in the sense that only the way in which the cells are attached can differ), or are there really examples where one can obtain X^n from X^(n-1) by using a different number of n-cells?
 
Physics news on Phys.org
quasar987 said:
Say X is a CW-complex. Then for any n, the n-skeleton X^n of X is obtained from the (n-1)-skeleton X^(n-1) by gluing some n-cells on X^(n-1) along their boundary.

From what I read, it seems that the way to obtain X^n from X^(n-1) in this way is not unique.

Is this non-uniqueness superfluous (in the sense that only the way in which the cells are attached can differ), or are there really examples where one can obtain X^n from X^(n-1) by using a different number of n-cells?

cell decompositions are not unique.

for instance,

the 2 sphere is a 2 disk whose boundary is attached to a point.
it is also a circle attached to a point then two 2 disks attached to the circle along their boundaries.
 
Hello wofsy and thanks for the reply.

But I don't think the example that you give answers my question. Let me rephrase it. If a CW-complex X has dimension n (meaning the maximum dimension of cells is n), then it is obtained from a (sub-)CW-complex X^(n-1) of dimension n-1 by attaching n cells to it. Is it possible to get X from X^(n-1) in two ways that involve a different amount of n-cells?

I'm guessing no but I don't see how to prove this.

Oh, I just noticed that the open n-cells in X are precisely the connected components of X\X^(n-1) so building X from X^(n-1) with a different numbers of n-cells is impossible!
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 18 ·
Replies
18
Views
3K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 33 ·
2
Replies
33
Views
3K
  • · Replies 0 ·
Replies
0
Views
3K
Replies
26
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K