What Are the Correct Tension Forces in Cables Lifting a 8Mg Tractor?

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SUMMARY

The discussion focuses on calculating the tension forces in cables AB, AC, and AD required to lift an 8Mg tractor. The user derived unit vectors for the cable forces and set up equations to solve for the magnitudes of the forces, resulting in values of b = c = -1.691Mg and d = -5.6218Mg. However, the calculated tension forces of |F_b| = 1.66E7 N and |F_d| = 5.51E7 N were found to be incorrect, prompting the user to seek clarification on their methodology.

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A tank hanging off a hook, what are the tension forces?

Homework Statement


2ahvas4.jpg

Determine the forces in cables AB, AC and AD needed to lift the tractor which has a mass of 8Mg.


Homework Equations





The Attempt at a Solution


I found the unit vectors of the three rope forces using the ropes' position vectors.

B = [-0.5241i -0.3276j -0.7861k]
C = [-0.5241i 0.3276j -0.7861k]
D = [0.31623i 0j -0.9487k]

So F_B = -9.8bB, F_C = -9.8cC and F_D = -9.8dD where b, c, d = magnitudes of the forces

Then I set up a system of equations to find b, c and d. I found:
b = c = -1.691Mg
d = -5.6218Mg

|F_b| = |F_c| = 9.8*1.691E6 = 1.66E7 N
|F_d| = 9.8*5.6218E6 = 5.51E7 N

But I checked and they aren't the right answers. What did I do wrong?
 
Last edited:
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Can no one help? :(
 

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