What Are the Escape Velocities for Callisto and a Neutron Star?

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SUMMARY

The escape velocity from Jupiter's moon Callisto, with a mass of 1.07 × 1023 kg and a radius of 2.4 Mm, is calculated to be 2438.73 m/s using the formula v=sqrt(2GM/r). For a neutron star with twice the mass of the sun (3.9782 × 1030 kg) and a radius of 6 km, the escape velocity is approximately 297,403,171.9 m/s. Both calculations confirm the use of the gravitational constant G=6.67 x 10-11 m3kg-1s-2 and the correct application of the escape velocity formula.

PREREQUISITES
  • Understanding of gravitational physics and escape velocity
  • Familiarity with the formula v=sqrt(2GM/r)
  • Knowledge of the gravitational constant G=6.67 x 10-11 m3kg-1s-2
  • Basic concepts of mass and radius in astrophysics
NEXT STEPS
  • Research the implications of escape velocity in astrophysical contexts
  • Explore the characteristics and formation of neutron stars
  • Learn about black holes and their relationship to neutron stars
  • Investigate the effects of gravity on different celestial bodies
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Astronomy students, astrophysicists, and anyone interested in the physics of celestial mechanics and escape velocities.

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Determine the escape speed from (a) Jupiter’s moon Callisto with a mass of 1.07 × 10^23 kg and radius 2.4 Mm and (b) a neutron star twice the mass of the sun and a radius of 6 km.

I want to make sure I'm doing this and have the correct equations..

For part a)
Okay, so escape speed is found using the equation
v=sqrt(2GM/r)
G=6.67 x 10^-11
M=1.07 × 10^23
r=2.4 x 10^6

v=sqrt(1.427 x 10^13/2.4 x 10^6)
v=srt(5947416.667)
v=2438.73 m/s

For part b)
v=sqrt(2GM/r)
G=6.67 x 10^-11
M=2(1.9891 ×10^30) = 3.9782 x 10^30
r=6000

v=sqrt(5.301 x 10^20/6000)
v=sqrt(8.845 x 10^16)
v=297403171.9 m/s
 
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Yep, you have the right formulae, and the right answers too.

and incase it is mentioned, your neutron star is VERY nearly a black hole too.
 

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