What are the forces acting on a stationary block with strings pulling on it?

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Homework Help Overview

The discussion revolves around a physics problem involving a stationary block on the ground with two strings exerting forces on it. The problem requires analysis of the forces acting on the block, specifically focusing on the normal force and static friction given the coefficients of friction and the forces applied by the strings.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the components of the forces acting on the block, particularly the vertical components of the tensions in the strings and how they relate to the gravitational force. There is also a consideration of the static friction force based on the normal force calculated.

Discussion Status

Some participants have provided calculations for the normal force and expressed concerns about the simplicity of the results. There is an ongoing exploration of the forces in the horizontal direction to determine the static friction force, indicating a productive direction in the discussion.

Contextual Notes

The problem includes specific values for the forces and angles involved, as well as the coefficient of static friction, which are critical for the calculations being discussed. The original poster expresses confusion regarding the setup due to the block being on the ground rather than suspended.

caela
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Hi Guys,

Having a super hard time with this homework question. I've done similar problems, but the fact that the box is ON the ground and not suspended is confusing me.

Quoted from my book:
"Two strings are pulling on a 50-kg block as shown. The block does not move. The coefficient of static friction between the floor and the block is µs=0.6
A. Find the magnitude of the normal force exerted by the floor on the block.
B. Find the magnitude of the static friction force exerted by the floor on the block."

http://tinypic.com/r/28kisrk/6
(The left string is 200 N with an angle of 53 degrees, and then right string is 100 N with an angle of 37 degrees, I know it's a little hard to read)

Thanks so much for any help! :)
 

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Hi. I would think of the components of the tensions in each string that are opposing the force of gravity...(100N*sin(37) is one of them)
 
Ok, so if I add up the two y values: 200cos(53) + 100cos(37) = 180
Then subtract the force of the box from the y values? 500 N-180 N = 320 N

And then for static friction, I would multiply 320 * .6 = 192?

It seems suspiciously easy...
 
Confirming your suspicion, nothing in Physics is particularly easy. You have calculated the Normal force correctly. You must now look in the x direction to get the friction force.
 

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