What Are the Key Variables in Projectile Motion on Planet Exidor?

Jeff231
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Homework Statement



A physics student on PLanet Exidor throws a ball, and it follows hte parabolic trajectgory shown in the figure. The ball's position is shown at 1.00 intervals until t=3.00. At t=1.00, the ball's velocity is v=(2.00i + 2.00j)[m/s].

physicsa.jpg


a. Determine the ball's velocity at t=0, 2.00, and 3.00.
b. What is the value of g on the Planet Exidor?
c. What was the ball's launch angle?

Homework Equations



[tex] v = v_0 + a t<br /> [tex] <br /> [tex] x = x_0 + v_0 t + (1/2) a t^2<br /> [tex] [tex] v^2 = v_0^2 + 2 a \Delta x<br /> [tex] <br /> <br /> <br /> <h2>The Attempt at a Solution</h2><br /> <br /> I was able to find at 1.00<s> that the ball's acceleration in the x direction = 2.00[m/s^2]. I'm not really sure how to find the velocity at t=0 <s> since I think it can't be zero. I'm pretty if I can figure out the max height I can figure out what g is. But I can't find max height. <br /> <br /> Thanks.<br /> </s></s>[/tex][/tex][/tex][/tex][/tex][/tex]
 
With all projectile motion problems you need to consider both components of motion. There should be no acceleration in the x direction. At the top of the parabola what do you expect the y component of velocity to be? This will help you with what you know about t = 1 to set up some simultaneous equations and solve the problem.
 
Kurdt said:
There should be no acceleration in the x direction.

It will really help to rewrite

[tex] v = v_0 + at = v_0 - gt[/tex]

where I've defined g downwards as positive as two equations then...

[tex] v_x = ... \quad \& \quad v_y = v_y(t)=...[/tex]
 
Thanks for the help. It was stupid of me to think of ax instead of just thinking g the whole time. This clarified things a bunch, thanks!
 

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