What are the lone pair angles in H2O according to VSEPR theory?

[alingy1]

Homework Statement

What are the angles between lone pairs in H2O? I know that the bonds are separated by 109.5°. What about the lone pair angles? I googled everything. I found nothing. I cannot directly assume it is 109.5°... I have a basic knowledge of VSEPR.

 

[DrDu]

I know that the bonds are separated by 109.5°.

Really? I thought it was 104.45 degrees.
In VSEPR, both bonding and lone pairs should be distributed approximately along the corners of a tetrahedron. Lone pairs are a bit more space filling than bonding pairs, so that the angle between the lone pairs is somewhat larger.

 

[Treedude]

I will double check my answers before posting.

 

[Borek]

H2O is bent. 109.5

H₂O is bent, but 109.5 is incorrect. Water molecule is not tetrahedral. DrDu already posted a correct value.