What are the meson 1p, 1d, 1f, states?

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    1d Meson States
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The discussion clarifies the distinction between atomic states and meson states, specifically addressing the absence of states like 1p, 1d, and 2d in atomic spectra, which follow the rule n = n_r + L + 1. In contrast, meson states such as 1p, 1d, and 1f are valid due to the use of the radial quantum number n_r in their classification, as outlined in the "Quark model" article in the PDG report. The principle quantum number n is unique to hydrogen atoms due to their energy degeneracy, which does not apply to mesons.

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mings6
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In atom spectrum, such as for hydrogen, there are states of 1s, 2s, 2p, 3s, 3p, 3d, etc. There are no 1p, 1d or 2d, 2f. Simply because n= n_r + L +1. So the maximum of L is n-1. But when I read articles talk about meson, they list meson states of 1p, 1d, 1f, etc. Such as in the article “Quark model” in the PDG report. What does these states come from? I am sure they use n ^(2s+1)L_j, and not the (n_r L), because they do not say 0s state. So what’s my mistake? Don’t meson has same rule of n= n_r + L +1?
 
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mings6, The "principle" quantum number n is unique to the Hydrogen atom because of its degeneracy: all the states with the same value of nr + L + 1 have the same energy.

This is not true in general, and so for listing the meson q-qbar states we use the radial quantum number nr instead, along with S, L and JPC.
 
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