What Are the Oxidation Numbers for Each Element in This Reaction?

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Discussion Overview

The discussion revolves around determining the oxidation numbers for each element in a chemical reaction involving silver sulfide and aluminum. Participants are tasked with identifying oxidation states and the oxidized and reduced reactants, with a focus on the chemistry of oxidation and reduction.

Discussion Character

  • Homework-related
  • Debate/contested
  • Technical explanation

Main Points Raised

  • One participant proposes oxidation numbers of Ag=2, S=-2, Al=0 for the reactants and Ag=-2, Al2=0, S=2 for the products.
  • Another participant challenges the initial interpretation, stating that the reaction does not represent silver tarnishing and claims that the oxidation numbers provided are incorrect, except for sulfur's oxidation state.
  • A different participant suggests alternative oxidation numbers of Ag=1, S=0, Al=1 for the reactants and Ag=-1, Al2=-1, S=0 for the products, asserting that Ag is reduced and Al is oxidized.
  • One participant requests clarification on how the oxidation numbers were calculated.
  • Another participant hints that sulfur's oxidation state remains unchanged during the reaction and questions the oxidation state of aluminum in the reactants.

Areas of Agreement / Disagreement

Participants do not reach consensus on the oxidation numbers or the characterization of the reaction. Multiple competing views and interpretations of the oxidation states and the nature of the reaction remain unresolved.

Contextual Notes

There are unresolved assumptions regarding the definitions of oxidation states and the context of the reaction being discussed. Participants have not fully clarified their calculations or reasoning processes.

chemjem
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Homework Statement



3Ag2 S + 2Al --> 6Ag + Al2 S3
consider the equation for silver tarnishing.
a) state the oxidation number for each element in the reaction.
b)identify the the oxidized reactant and the reduced reactant.




The Attempt at a Solution



Ag2=2 S= -2 Al=0 ---> Ag=-2 Al2=0 S=2

Ag2 loses the electron so it is the oxidized reactant.
S gains the electron so it is the reduced reactant.

am i close to having the right answer?
 
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Not really. This isn't really a silver tarnishing reaction. It is the opposite of a silver tarnishing reaction. Tarnishing involves the reaction of zero valent metal to its oxidized form.

Yes, the sulfur atom in silver sulfide is at an oxidation state of -2. Literally everything else you have written is incorrect.

Try again. You are on the right track.
 
thanks for the reply. chemistry is not my thing... i am trying.
 
If you try, I'll reply.
 
Ag2=1 S=0 Al=1 ---> Ag=-1 Al2=-1 S=0

Ag gains the electron so it is reduced
Al loses the electron so it is oxidized
 
I'll give you a hint: The sulfur (-2) does not change oxidation state during the reaction. It only swaps partners.

What is the oxidation state of aluminum in the reactant side of the equation (...+ 2Al -->)?
 

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