What are the possible values of x and y in the equation x + 2y > 5?

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Discussion Overview

The discussion revolves around the inequality x + 2y > 5, exploring possible values for x and y. Participants engage in mathematical reasoning and clarification of steps taken to derive inequalities from the original expression.

Discussion Character

  • Mathematical reasoning
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • Some participants express confusion over the derivation of the inequality x + y > 2.5 from x + 2y > 5.
  • One participant suggests that dividing the inequality by 2 leads to a different form, specifically $\frac{x}{2}+y>2.5$.
  • Another participant questions the validity of dividing by 2, indicating it may lead to incorrect conclusions about the values of x and y.
  • There is mention of the need to consider positive integers when determining values for x and y.
  • Some participants apologize for the confusion in their earlier posts, indicating a lack of clarity in their explanations.

Areas of Agreement / Disagreement

Participants express uncertainty regarding the correct approach to solving the inequality, with no consensus reached on the best method or the implications of dividing by 2.

Contextual Notes

Participants highlight potential misunderstandings in the manipulation of inequalities and the assumptions regarding the nature of x and y (e.g., positive integers). There are unresolved steps in the mathematical reasoning presented.

squexy
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View attachment 3780

1
x + 2y > 5
x +y> 2,5 (.-1)

x + 2y > 2,5
-x - y > -2,5

y > 2,5
x> 0

View attachment 3779Log 9 - log 4´= log 5

5 * log 5 =
2^5 * 0,6989
2^3,4948
11,27300
 

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squexy said:
View attachment 3780

1
x + 2y > 5
x +y> 2,5 (.-1)

x + 2y > 2,5
-x - y > -2,5

y > 2,5
x> 0

How did you get the second inequality? (Thinking)
 
evinda said:
How did you get the second inequality? (Thinking)

My apologies, the post was confusing.

n= 5
x + 2y = n
x + 2y > 5
x +y> 2,5
-x - y > -2,5
y > 2,5 - xx+2y > 5
x + 2(2,5 -x) > 5
x>0

x+y>2,5
y > 2,5
 
squexy said:
My apologies, the post was confusing.

n= 5
x + 2y = n
x + 2y > 5
x +y> 2,5
-x - y > -2,5
y > 2,5 - xx+2y > 5
x + 2(2,5 -x) > 5
x>0

x+y>2,5
y > 2,5
How did you get to the inequality $x+y>2.5$ ?
 
evinda said:
How did you get to the inequality $x+y>2.5$ ?

I divided 5 by 2.
x + 2y > 5
x + y > 5/2
x + y > 2,5
 
squexy said:
I divided 5 by 2.
x + 2y > 5
x + y > 5/2
x + y > 2,5

If you want to divide by 2, the inequality will become $\frac{x+2y}{2} > \frac{5}{2} \Rightarrow \frac{x}{2}+y>2.5$.
 
evinda said:
If you want to divide by 2, the inequality will become $\frac{x+2y}{2} > \frac{5}{2} \Rightarrow \frac{x}{2}+y>2.5$.

So I should not divide by 2 otherwise I will get x=0, I must be wrong from the begging how could I start to solve the 1 question?
 
squexy said:
So I should not divide by 2 otherwise I will get x=0, I must be wrong from the begging how could I start to solve the 1 question?

We add $x$ to $2y$ in order to get $n$. So notice that both of them have to be $\leq n$. You also have to take into consideration the fact that we are looking for positive integers.
 

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