What are the possible x values for finding a limit in this problem?

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The discussion centers on determining the possible x values for finding limits in the expression \(\frac{x-2}{x-3}\). The correct interpretation of the limit involves recognizing that as x approaches specific values, particularly negative infinity, 0, positive infinity, or +3, the behavior of the function changes. The expression simplifies to \(1 + \frac{1}{x-3}\), which is crucial for understanding the limit's behavior at these points. The conversation emphasizes the importance of defining the expression at the chosen x value to accurately find the limit.

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This is very basic. I have asked some friends and they don't know. I have tried resolving it by long division, and can see where the 1 comes from but the remainder is 1. I have gone back to the basics, but the operands are multicative. ie 1/a * a = 1
What is the algebra of this

The problem in taking limits: Notice that, by division x-2/x-3 = 1 + 1/ x-3.
 
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What is x approaching on your limit?
 
This is not what you meant:
x-2/x-3 = 1 + 1/ x-3

You wished to say, [itex]\frac{x-2}{x-3}=1+\frac{1}{x-3}[/itex]

What does x approach for which you want to find a limit? Is the expression defined at that x value?

Most likely you are interested in one of these:

  • x approaches negative infinity
    x approaches 0
    x approaches infinity
    x approaches +3
 

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