Let's take it from here:Doc Al said:You took the cube root of 8 (81/3) and then cubed it. Why?
The limit would be 256.Delta2 said:Yes the limit is 1/2. If we tweak the function and we make it so that f(x) is the same as before for all ##x\neq 8## but we set ##f(8)=256## what will the limit be?
Nope it will remain 1/2. For the limit we focus what happens around the point of interest but not necessarily onto the point of interest. Around 8 the tweaked function remains the same so the limit remains the same. I just introduced an artificial discontinuity in the tweaked function by setting f(8)=whatever except 1/2.nycmathguy said:The limit would be 256.
What are limits doing in a pre-calculus book, one wonders?Delta2 said:Nope it will remain 1/2. For the limit we focus what happens around the point of interest but not necessarily onto the point of interest. Around 8 the tweaked function remains the same so the limit remains the same. I just introduced an artificial discontinuity in the tweaked function by setting f(8)=whatever except 1/2.
I guess you need to be introduced to continuity and discontinuity by your textbook. If it is not done by your precalculus book, it should be done by your calculus I book.
The boundaries between calculus and precalculus are fuzzy, at least that's what Ron Larson thinks lol...PeroK said:What are limits doing in a pre-calculus book, one wonders?