What Are the Solutions to These Circular Motion Problems?

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SUMMARY

This discussion focuses on solving circular motion problems using centripetal acceleration formulas. Key equations include centripetal acceleration defined as a = v²/r and a = ω²r, where v is linear velocity, r is radius, and ω is angular velocity. Participants provided solutions for various questions involving circular motion, including calculating distances and accelerations based on given parameters. The discussion highlights the importance of accurate diagramming and applying geometric principles to solve these problems effectively.

PREREQUISITES
  • Centripetal acceleration concepts
  • Understanding of angular velocity (ω)
  • Basic geometry of circles
  • Familiarity with linear velocity (v)
NEXT STEPS
  • Study the derivation of centripetal acceleration formulas
  • Learn how to apply angular velocity in practical problems
  • Explore the relationship between linear and angular motion
  • Practice solving circular motion problems with varying parameters
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and circular motion, as well as educators seeking to enhance their teaching methods in these topics.

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Homework Statement


IMG.jpg



Homework Equations


Centripetal Acceleration: a=v2/r or a=w2r
where a= Centripetal Acceleration
v= Linear Velocity
r= Radius
w=angular velocity


The Attempt at a Solution


Question Number 1: Drew a diagram of a circular with one point being O, another being P and another being A, Radius of Circle is 3.6m, and joined O and P to a 25o
MIGHT BE WRONG

Question Number 2:
Turn of 90o takes 0.4 seconds
Therefore 90degree/0.4 seconds = 225 degrees per second or
Therefore using equation
a=w2r
a=2252*0.45
a=22781.25degrees/sec

Pretty sure this is also wrong as for acceleration, it seems too fast

Question Number 3:
Drew diagram--> Circle[Radius 12 cm][2 Revolutions per second]
a=w2r


Question Number 4:
Honestly have no idea how to start
 
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For 1, since the speed on and off the circular path remains constant, then the distanced traveled in an equal amount of time is identical. This means OA = OP. What remains is to calculate OP which can be done using simple circle geometry.

For 2 and 3, you look to be on the right track.

For 4, consider the block's motion. Since the car follows a circle of radius 150m at a speed of 8m/s the block must do the same. The string is the thing accelerating the block, so the angle will be such that the tension offers the suitable amount of centripetal acceleration.
 
Thanks Yuqing
For question 1, pretty sure its correct!
Due to fact speed of object is identical(from OP to OA), and also same time, therefore DistanceOA = Distance OP

Find circumference of circle then find length of 25degree

Therefore
C(25degree)= 2*pi*3.6*(25/360)
C(25degree)=1.57m

Thanks

now for Q2-4!
 

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