# Gravitational acceleration in circular motion

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• physicsmagician
In summary, the question is where the acceleration of 9.8 meters per second squared goes in uniform circular motion, since it doesn't seem to change the speed. However, in this case, acceleration is changing velocity, not speed, and in circular motion it doesn't change the magnitude of the vector. The concept of a conical pendulum may provide further understanding on this topic.
physicsmagician
Hi guys, I have a question that is simple but I do not know how to answer that. It is the following, where does the acceleration of 9,8 meters per second squared go when We're dealing with uniform circular motion? I know that We have the centripetal acceleration that is a vector change, but the value of 9,8 I said, where did it go?

$$a=\frac{v^2}{r}$$
You should set values of speed v and radius r to get a=9.8 m/sec^2.

If you are talking on sum of gravity force or acceleration and centrifugal force or acceleration, Conical pendulum https://en.wikipedia.org/wiki/Conical_pendulum might be of your interest.

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physicsmagician
What do you mean "where does it go"? Are you asking why the speed doesn't change? If so, the point is that acceleration doesn't change speed, it changes velocity. In the particular case of circular motion it happens not to change the magnitude of the vector, that's all.

physicsmagician and vanhees71

## 1. What is gravitational acceleration in circular motion?

Gravitational acceleration in circular motion is the acceleration experienced by an object moving in a circular path due to the force of gravity. It is the rate at which the object's velocity changes as it moves around the circle.

## 2. How is gravitational acceleration related to centripetal acceleration?

Gravitational acceleration is one component of centripetal acceleration, which is the acceleration towards the center of a circular path. The other component is tangential acceleration, which is the change in velocity along the tangent of the circle.

## 3. What is the formula for calculating gravitational acceleration in circular motion?

The formula for gravitational acceleration in circular motion is a = v2/r, where a is the acceleration, v is the velocity, and r is the radius of the circle.

## 4. Does gravitational acceleration change with the mass of the object?

No, gravitational acceleration is a constant value and does not depend on the mass of the object. This is because the acceleration due to gravity is determined by the mass of the larger object (such as the Earth) and not the smaller object (such as a satellite in orbit).

## 5. How does the radius affect gravitational acceleration in circular motion?

The radius of the circle affects gravitational acceleration in circular motion by determining the amount of centripetal force required to keep the object in its circular path. A larger radius requires a smaller acceleration, while a smaller radius requires a larger acceleration.

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