What are the tensions in the strings for a rotating object?

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In summary, the problem involves a 4.95 kg object rotating in a horizontal circle at a constant speed of 7.25 m/s. The object is attached to a vertical rod by two strings, with a length of 2.00m each, and the rod has a length of 3.00m. Using the equation for radius, the radius is determined to be 1.32m. The centripetal force is found by using the centripetal acceleration formula and the problem can be solved using trigonometry to find the tension in the upper and lower strings.
  • #1
tnhoots
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More tension prolbmes!

Homework Statement



A 4.95 kg object is attached to a vertical rod by two strings. The object rotates in a horizontal circle at constant speed 7.25 m/s. the length of both strings is 2.00m and the length of the verticle rod is 3.00m.

(a) Find the tension in the upper string.
N
(b) Find the tension in the lower string.
N



Homework Equations



equation for radius: r^2=c^2 - b^2

The Attempt at a Solution



radius equals 1.32m
 
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  • #2
If i could have a picture of the set or something..
 
  • #3
I could not copy and past the pic...it wouldn't let me paste it on here. It's pretty much a verticle rod with a string coming from the top and the bottom corners to form a triangle. That's the best way I know how to depict it. Sorry
 
  • #4
tnhoots said:
I could not copy and past the pic...it wouldn't let me paste it on here. It's pretty much a verticle rod with a string coming from the top and the bottom corners to form a triangle. That's the best way I know how to depict it. Sorry

You can upload the image by going to http://imageshack.us, and clicking "Browse". Then just locate the image on your hard drive and press upload. Use the link you are given to show the picture.
 
  • #6
Hope this helps us all out...I know I need it!
 
  • #7
What is the centripetal force?
 
  • #8
the cent. acceleration is v^2/r. Which is 19.6^2/10=38.416
 
  • #9
The problem is pretty straight forward. The acceleration only has one component which is the radial one, so the speed is constant. Use trigonometry to find the radius and to set the component of the tension in the direction of the radial acceleration.
 

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