What are the tensions in the strings of a 3.60 kg object in circular motion?

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SUMMARY

The discussion focuses on calculating the tensions in two strings supporting a 3.60 kg object in circular motion at a constant speed of 7.20 m/s. The key equations involved are T=mg/cos(theta) and m(v^2/r)=T*sin(theta). The user initially attempted to solve for the radius and angle but encountered errors due to not accounting for the two different tension forces acting on the object. A free body diagram is recommended for accurately summing the forces in each direction.

PREREQUISITES
  • Understanding of circular motion dynamics
  • Familiarity with tension force calculations
  • Knowledge of free body diagrams
  • Basic trigonometry for resolving forces
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  • Study the principles of circular motion and centripetal force
  • Learn how to draw and analyze free body diagrams
  • Explore the relationship between tension forces in multi-string systems
  • Review trigonometric functions in physics applications
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This discussion is beneficial for physics students, educators, and anyone involved in mechanics, particularly those studying circular motion and tension forces in multi-string systems.

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***circular motion!***

Homework Statement


http://www.webassign.net/pse/p6-11.gif
A 3.60 kg object is attached to a vertical rod by two strings as in Figure P6.11. The object rotates in a horizontal circle at constant speed 7.20 m/s.


(a) Find the tension in the upper string.

(b) Find the tension in the lower string.

Homework Equations



T=mg/costheta
m(v^2/r)=Tsintheta


The Attempt at a Solution



I tried to solve for r and i got 1.32 but when i plugged it into the equation for tension it said it was wrong. i tried to solve for theta and got 41.3 in order to plug into the equation and it was wrong as well. what am i doing wrong??
 
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I think you are forgetting there are two strings. You can't use your equation and do each string separately. You need two different tension forces in your equations. Draw a free body diagram of the ball and sum up the forces in each direction like you would do for any other force problem.
 

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