What are the tensions in the strings of an accelerating elevator?

  • Context: MHB 
  • Thread starter Thread starter cbarker1
  • Start date Start date
  • Tags Tags
    Elevator Tension
Click For Summary
SUMMARY

The discussion focuses on calculating the tensions in two strings supporting spheres in an elevator under different acceleration scenarios. For a downward acceleration of 1.45 m/s², the tensions are derived using the equations of motion, resulting in specific values for T1 and T2. When the elevator accelerates upward with the same acceleration, the tensions change accordingly, necessitating a different set of calculations. Additionally, the maximum upward acceleration before the strings break is determined by the maximum tension limit of 80.0 N.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Basic knowledge of tension in strings and forces
  • Ability to solve algebraic equations
  • Familiarity with free body diagrams
NEXT STEPS
  • Learn how to apply Newton's second law in multi-body systems
  • Study the concept of tension in different physical scenarios
  • Explore the effects of varying acceleration on tension in strings
  • Investigate the limits of material strength and failure analysis
USEFUL FOR

Physics students, mechanical engineers, and anyone interested in dynamics and the behavior of forces in accelerating systems.

cbarker1
Gold Member
MHB
Messages
345
Reaction score
23
Dear Everyone,

A sphere is attached to the ceiling of an elevator by a string. A second sphere is attached to the first one by a second string. Both strings are of negligible mass. Here $m_1=m_2=m=3.52\text{ kg}$.

4-p-064.gif


(a) The elevator starts from rest and accelerates downward with $a=1.45\,\dfrac{\text{m}}{\text{s}^2}$. What are the tensions in the two strings?

(b) If the elevator starts from rest and accelerates upward with the same acceleration, what will be the tension in the two strings?

(c) The maximum tension the two strings can withstand is 80.0 N. What maximum upward acceleration can the elevator have without having one of the strings break?

I would need to some help to setup and find the value of Tension of the cable one.

Thanks,

Cbarker1
 
Mathematics news on Phys.org
(a) ...

$m_2g - T_2 = m_2 a$

$m_1g+T_2-T_1 = m_1 a$

------------------------------ sum the two scalar equations ...

$(m_1+m_2)g - T_1 = (m_1+m_2)a$

$(m_1+m_2)g - (m_1+m_2)a = T_1$

evaluate $T_1$, then determine $T_2$(b) ...

$T_1 - (m_1g + T_2) = m_1a$

$T_2 - m_2g = m_2a$

same drill ...

I'll leave part (c) for you to try
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 12 ·
Replies
12
Views
1K
  • · Replies 10 ·
Replies
10
Views
4K
  • · Replies 9 ·
Replies
9
Views
714
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 10 ·
Replies
10
Views
6K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 31 ·
2
Replies
31
Views
3K