What are the two equations for Centripetal Force

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SUMMARY

The discussion centers on the equations for Centripetal Force, specifically the formula F = m(v²/r), where F represents Centripetal Force, m is mass, v is velocity, and r is radius. The user successfully isolated mass but encountered difficulties rearranging the equations to solve for radius and velocity. The substitution of velocity with the expression 2πr/T, where T is the period, complicates the equations, leading to confusion when r appears on both sides of the equation. The user seeks assistance in simplifying these equations for clarity.

PREREQUISITES
  • Understanding of Centripetal Force and its formula F = m(v²/r)
  • Knowledge of the relationship between velocity, radius, and period (v = 2πr/T)
  • Algebraic manipulation skills for rearranging equations
  • Familiarity with basic physics concepts related to circular motion
NEXT STEPS
  • Learn how to isolate variables in physics equations
  • Study the derivation of Centripetal Force equations
  • Explore examples of circular motion problems involving Centripetal Force
  • Investigate the relationship between diameter and radius in circular motion
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Students studying physics, particularly those focusing on mechanics and circular motion, as well as educators seeking to clarify concepts related to Centripetal Force and its applications.

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Homework Statement

I have to rearange both equations to find mass, radius, and velocity (each of them separately).



Homework Equations

I know that Centripetal Force= mass x (velocty^2/radius). In this case velocity is also equal to 2∏r/T (where T is the period), so I subsituted that in for v for the first equation and used it as the second. The experiment we did involved the period value, so I assumed that's what he wanted.



The Attempt at a Solution

I was able to isolate the mass the just fine, it's when I try to find radius and velocity that complicate it. When I solve it for the second for radius however, I have r on both sides of the equation. For velocity, I just get the quantity 2∏r/T on one side with the rest on the other. It just looks messy to me. I was thinking for the radius issue, I could get rid of the r on the other side of the equation by making it 1/2(diameter)? I'm lost here. I'd appreciate some help.
 
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I was able to isolate the mass the just fine, it's when I try to find radius and velocity that complicate it. When I solve it for the second for radius however, I have r on both sides of the equation. For velocity, I just get the quantity 2∏r/T on one side with the rest on the other. It just looks messy to me. I was thinking for the radius issue, I could get rid of the r on the other side of the equation by making it 1/2(diameter)? I'm lost here. I'd appreciate some help.
Can you post those equations? It is hard to spot specific problems based on that description.

You want get equations of the type ##v=...## and ##r=...## from ##F=m\frac{v^2}{r}##?
 

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