What are the unit eigenvectors for the matrix A = [5 -2; -2 8]?

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The unit eigenvectors for the matrix A = [5 -2; -2 8] are derived from the eigenvalues lambda = 4 and lambda = 9. The unit eigenvector corresponding to lambda = 4 is x1 = (-2/sqrt(5), -1/sqrt(5))^T, while the unit eigenvector for lambda = 9 is x2 = (1/sqrt(5), -2/sqrt(5))^T. The calculations appear to be correct based on the determinant equation det(A - hI) = 0. Confirmation from others in the discussion indicates agreement with these results. The findings are consistent and validated by peer feedback.
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Homework Statement



I'm trying to find the unit eigenvectors corresponding to the following matrix

A = [5 -2; -2 8] ; means new row

Homework Equations



det(A - hI) = 0

The Attempt at a Solution



I get lambda = 4 and 9

unit eigenvector corresponding to lambda = 4

x1 = ( -2/sqrt(5), -1/sqrt(5) )^T

unit eigenvector corresponding to lambda = 9

x2 = (1/sqrt(5), -2/sqrt(5) )^T

Could someone please let me know if they get the same result. Thanks!
 
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Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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