What are the values of $a$ and $b$ in this limit?

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The limit problem presented is $$\lim_{{x}\to{0 }}\frac{\sqrt{ax+b}-2 }{x}=1$$, where the values of $a$ and $b$ must be determined. It is established that for the limit to exist, the expression must yield a 0/0 form, leading to the conclusion that $b = 4$. Applying L'Hôpital's rule, the derivative of the numerator at $x=0$ gives $\frac{a}{2\sqrt{4}}=1$, resulting in $a=4$. Thus, the definitive values are $a = 4$ and $b = 4$.

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$$\lim_{{x}\to{0 }}\frac{\sqrt{ax+b}-2 }{x}=1$$
Find $a$ and $b$

Clueless!
 
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For the limit to exist, that expression must be of the form 0/0, so b = 4. Now use L'Hopital's rule to finish up.
 
so at dx $0/0$ the denominator goes to $1$ then

dx of $\sqrt{ax+4}-2$ is $\frac{a}{2\sqrt{ax+4}}$

$x\to0$ $\frac{a}{2\sqrt{4}}=1$ $a=4$

actually can't $a$ be anything
 
Last edited:
Are there any other solutions to the equation $$\frac{a}{2\sqrt4}=1$$?
 
no quess not.
 

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