- #1
xyz_1965
- 73
- 0
Let theta be 15 degrees.
Here is my set up.
To find x, use tan (15°) = x/200.
To find y, use cos (15°) = 200/y.
MHB What are the values of x and y when theta is 15 degrees?
- Thread starter xyz_1965
- Start date
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To find the values of x and y when theta is 15 degrees, the equations tan(15°) = x/200 and cos(15°) = 200/y are established. Solving for x gives x = 200 * tan(15°). For y, rearranging the equation results in y = 200/cos(15°). These calculations provide the necessary values for x and y based on the given angle.
Let theta be 15 degrees.
Here is my set up.
To find x, use tan (15°) = x/200.
To find y, use cos (15°) = 200/y.
- #2
Monoxdifly
MHB
- 288
- 0
Yes, you can proceed from there.
Obviously, there is something elementary I am missing here.
To form the transpose of a matrix, one exchanges rows and columns, so the transpose of a scalar, considered as (or isomorphic to) a one-entry matrix, should stay the same, including if the scalar is a complex number. On the other hand, in the isomorphism between the complex plane and the real plane, a complex number a+bi corresponds to a matrix
in the real plane; taking the transpose we get
which then corresponds to a-bi...
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