What are the x- and y-components of the velocity vector?

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Homework Help Overview

The problem involves determining the x- and y-components of a velocity vector based on a provided figure. The context is within the subject area of vector decomposition in physics.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the calculations for the components of the velocity vector, with one original poster attempting to use trigonometric functions but questioning their approach after receiving feedback. Another participant raises a question about the angles formed with the axes.

Discussion Status

The discussion is ongoing, with some guidance provided regarding the use of sine and cosine in the context of the problem. Participants are exploring different interpretations of the vector's orientation and its components.

Contextual Notes

There is a reference to a figure that is essential for understanding the problem, but it is not included in the discussion. Additionally, one participant notes that a previous contributor is no longer active in the forum.

jamal.kun
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Homework Statement


Question is: What are the x- and y-components of the velocity vector shown in the figure?
knight_Figure_03_22.jpg


https://session.masteringphysics.com/problemAsset/1384003/6/knight_Figure_03_22.jpg

The Attempt at a Solution


I tried -100 m/s*cos(30 degrees)=-86.6m/s for the x component and -100m/s*sin(30 degrees)=-50m/s for the y component, but was incorrect for both. What am I missing?
 
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jamal.kun said:

Homework Statement


Question is: What are the x- and y-components of the velocity vector shown in the figure?
knight_Figure_03_22.jpg


https://session.masteringphysics.com/problemAsset/1384003/6/knight_Figure_03_22.jpg

The Attempt at a Solution


I tried -100 m/s*cos(30 degrees)=-86.6m/s for the x component and -100m/s*sin(30 degrees)=-50m/s for the y component, but was incorrect for both. What am I missing?

Welcome to the PF.

You got the sin & cos backwards. Try drawing the line from the tip of the vector to the negative y axis. See how the component of the vector on the negative y-axis involves the cos(30 degrees)?
 
Thanks berkeman, I see what you mean now. I didn't expect something like that. Thank you for the incredibly quick reply.
 
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If we drawing the line from the tip of the vertor to the negative y-axis then What will be its angle with x axis and negative y-axis?
 
Abdullah Wali said:
If we drawing the line from the tip of the vertor to the negative y-axis then What will be its angle with x axis and negative y-axis?
If you are asking jamal.kun, the thread is seven years old and jamal is no longer a forum member.
 

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