What CM frame to take in this case?

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In summary, the CM frame refers to the frame where the total spatial momentum is zero, and in this frame, the initial electron-positron pair will have a total four-momentum of (E1+E2, 0). However, by conservation of four-momentum, the fermion pair will also have a total four-momentum of (E1'+E2', 0). The direct production of a Higgs in an electron-positron collision is unlikely due to the small mass of the particles, but it is possible in high-energetic collisions. The method for finding invariants in this case will depend on what specific invariants are being sought.
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physciencer
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If an electron-positron is decaying into Higgs and then from Higgs into fermions. What is CM frame in this case?

Let us say that electron has momentum $$p_{e^-}=p_1$$ The positron has a momentum $$p_{e^+}=p_2$$ The fermion has momentum $$ p_{f} = q_1$$ and the other one has momentum $$p_{\bar{f}}=q_2$$
 
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  • #2
The CM frame is always the same, i.e. the one where the total spatial momentum is zero. In this frame you have that the initial e+e- pair have total four-momentum ##p_1+p_2=(E_1+E_2, \vec{0})##. However, by conservation of four-momentum it must also be ##q_1+q_2=(E_1^\prime+E_2^\prime, \vec{0})##.
 
  • #3
physciencer said:
If an electron-positron is decaying into Higgs
That does not make sense - neither the electron nor the positron can decay to a Higgs, and a combined object (positronium) cannot do either.

You can produce a Higgs in a high-energetic collision of electrons and positrons, but the direct production (a Higgs and nothing else) is very unlikely due to the small mass of the particles.
 
  • #4
SO yes that is what I meant, that you can produce a Higgs in that way. If so, then the CM is how @Einj posted, no?

@Einj, how would I find invariants in this case?
 
  • #5
It depends on what invariants you want to find. What do you have in mind?
 

What CM frame means in the context of physics?

The CM frame, or center-of-mass frame, refers to the reference frame in which the total momentum of a system is zero. In this frame, the center of mass of the system remains at a fixed point and the motion of individual particles can be described more simply.

Why is it important to choose the appropriate CM frame in a physics experiment or calculation?

Choosing the appropriate CM frame is important because it simplifies the analysis of a system and makes it easier to apply fundamental laws of physics, such as conservation of momentum and energy. It also allows for a more accurate understanding of the system's dynamics and behavior.

How do I determine which CM frame to take in a particular case?

The choice of CM frame depends on the specific system and the goal of the experiment or calculation. In some cases, it may be convenient to choose a CM frame that is at rest or moving at a constant velocity. In other cases, it may be more beneficial to choose a CM frame that is rotating or accelerating. It is important to carefully consider the system and its dynamics before choosing a CM frame.

What are the advantages and disadvantages of choosing a specific CM frame?

The advantages of choosing a specific CM frame include simplifying the analysis of a system, making it easier to apply fundamental laws of physics, and providing a more accurate understanding of the system's dynamics. However, the disadvantage is that it may not always be possible to choose a CM frame that perfectly fits the system, and some calculations or experiments may be more complex in a non-inertial CM frame.

Can the CM frame be changed during an experiment or calculation?

Yes, the CM frame can be changed during an experiment or calculation if it is necessary for the analysis or if new information is discovered. However, it is important to carefully consider the implications and potential effects of changing the CM frame on the results and conclusions of the experiment or calculation.

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