What Could Be Wrong with My Wave Function Equation?

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SUMMARY

The wave function for a simple harmonic oscillator at x=0 with a frequency of 40 Hz and amplitude of 3.00 cm is derived using the formula y(x,t) = A cos(kx - wt). The correct parameters are A = 0.03 m, k = 8π, and w = 80π. The error in the initial equation arises from not converting the amplitude to meters and potentially miscalculating the wavelength. The correct wave function is y(x,t) = 0.03 cos(8πx - 80πt).

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lina29
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A simple, harmonic oscillator at the point x=0 generates a wave on a rope. The oscillator operates at a frequency of 40 Hz and with an amplitude of 3.00 cm. The rope has a linear mass density of 50.0 g/m and is stretched with a tension of 4.50 N.

Write the wave function y(x,t) for the wave moving in +x-direction. Assume that the oscillator has its maximum upward displacement at time t=0.

I know to write the wave function I use the equation y(x,t)=Acos(kx-wt)
where A=3, k=2pi/[tex]\lambda[/tex]=8pi, w=2pif=80pi

So I got the equation y(x,t)=3cos(8pi x-80pi t)

However when I put it in it says the equation is wrong

Can anyone help me in figuring out what I missed?
Thanks
 
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How did you calculate the wavelength?
 
Make sure the amplitude is in meters, so 0.03 should be the amplitude
 

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