What Determines the Center of Mass Energy in Particle Collisions?

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SUMMARY

The center of mass energy (ECM) in particle collisions is determined by the total energy and momentum of the colliding particles. In the Hermes experiment, with a 27 GeV electron beam colliding with a stationary proton (mass 1 GeV/c²), the ECM can be calculated using the equation ECM = √(E²_total - p²_total c²). For identical particle beams with energy 4mc², the ECM varies based on their collision configuration: head-on, 90-degree, or parallel. Understanding these calculations is crucial for analyzing particle interactions in high-energy physics.

PREREQUISITES
  • Understanding of special relativity and energy-momentum relations
  • Familiarity with the concept of center of mass energy
  • Basic knowledge of particle physics, specifically electron and proton interactions
  • Proficiency in using the equations for energy and momentum in relativistic contexts
NEXT STEPS
  • Study the derivation of the center of mass energy formula in particle physics
  • Learn about the implications of different collision angles on ECM
  • Explore the role of massless particles in high-energy collisions
  • Investigate the Hermes experiment and its contributions to particle physics
USEFUL FOR

Physicists, students of particle physics, and researchers interested in high-energy collisions and the fundamental principles governing particle interactions.

nastassja
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Homework Statement



a. The Hermes experiment is a fixed target experiment. The HERA accelerator creates circulating beams of electrons of energy 27 GeV; these are repeatedly crashed into a target of protons which are at rest. What is the center of mass energy of the electron-proton collisions?

Use 1 GeV/c2 as the mass of the proton. Treat the electrons as massless.
b.
c. (Both of these are based on the answer of the first, and I think I can figure them out if I understand part a.)

d. Consider two beams of identical particles with rest mass m; each beam has energy 4mc2. What is the center of mass energy ECM of the two beam system in the following cases:
--beams 1 and 2 are antiparallel (head on collision)
--beams 1 and 2 are directed in the +x and +y directions respectively (90\circ collision)
--beams 1 and 2 are parallel: both momenta are along the +x direction.


Homework Equations



ECM=\sqrt{E^{2}_{total}-(p_{total})^{2}c^{2}}
E=pc for massless particles.

The Attempt at a Solution



I only have a couple questions, and I should be able to figure out the rest on my own.

a. For the total energy, I'm guessing we just add the energy of the protons to the energy of the electrons, but how would you determine the energy of the protons? Since their momentum is zero, should it just be E=mc2?

d. I'm completely lost on how to do the second one. The first and last seem fairly simple as long as I keep track of my signs, but I'm not sure how to express the momentum in terms of m and c.
 
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(a) E_cm = [ (E_1+E_2)^2 - ( p_1_vector + p_2_vector)^2];

I think yes. E_2 is just rest mass energy of proton.

(b) E_cm = [ E_1^2 + 2*E_1*E_2 + E_2^2 - p_1^2 - p_2^2 -2*p_1*p_2* cos (90 degree) ]^(1/2)
= [ ( E_1^2 - p_1^2) + ( E_2^2 - p_2^2) + 2* E_1 * E_2 ]^(1/2)
= [ m^2 + m^2 + 2 * (4*m) * (4*m) ]^(1/2)
= [ 34 m^2 ]^(1/2)
I have confusion about beam energy. Is this right to put E_1=E_2= 4m ? Please correct me if I am wrong.

I have another question. What is the physical meaning of center of mass energy?
 

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